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# (1/5)^−2∗(1/25)^−4∗(1/125)^−6 =

Author Message
Senior Manager
Joined: 18 Feb 2019
Posts: 380
Location: India
GMAT 1: 460 Q42 V13
GPA: 3.6

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Updated on: 11 Apr 2019, 04:18
00:00

Difficulty:

65% (hard)

Question Stats:

57% (01:45) correct 43% (01:17) wrong based on 21 sessions

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$$(\frac{1}{5})^{−2}∗(\frac{1}{25})^{−4}∗(\frac{1}{125})^{−6} =$$

A. 125^-7
B. 625^-7
C. 125^7
D. 625^7
E. 625^14

Originally posted by kiran120680 on 10 Apr 2019, 12:34.
Last edited by chetan2u on 11 Apr 2019, 04:18, edited 2 times in total.
Corrected the OA
Math Expert
Joined: 02 Aug 2009
Posts: 7686

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11 Apr 2019, 04:15
kiran120680 wrote:
$$(\frac{1}{5})^{−2}∗(\frac{1}{25})^{−4}∗(\frac{1}{125})^{−6} =$$

A. 125^-7
B. 625^-7
C. 125^7
D. 625^7
E. 625^14

OA is wrong... answer should be D and NOT E..That is why timer is also showing 100% wrong

$$(\frac{1}{5})^{−2}∗(\frac{1}{25})^{−4}∗(\frac{1}{125})^{−6}$$ = $$5^2*25^4*125^6=5^2*(5^2)^4*(5^3)^6=5^{2+2*4+3*6)=5^28=(5^4)^{\frac{28}{4}}=625^7$$
D
_________________
Re: (1/5)^−2∗(1/25)^−4∗(1/125)^−6 =   [#permalink] 11 Apr 2019, 04:15
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