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# 1+2x+3x^2+4x^3+.............nx^(n-1) Whats the sum of the

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Director
Joined: 18 Feb 2005
Posts: 669
1+2x+3x^2+4x^3+.............nx^(n-1) Whats the sum of the [#permalink]

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20 Mar 2005, 06:29
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1+2x+3x^2+4x^3+.............nx^(n-1)

Whats the sum of the series?
Intern
Joined: 19 Jul 2004
Posts: 43

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20 Mar 2005, 06:55
gmat2me2 wrote:
1+2x+3x^2+4x^3+.............nx^(n-1)

Whats the sum of the series?

Let S = 1+2x+3x^2+4x^3+.............nx^(n-1) ... (1)

Multiply both sides by 'x'

xS = x + 2x^2+ 3x^3+.............nx^(n) ... (2)

Subtract (2) from (1)

S (1- x) = 1 + x + x^2 + ..... + x^(n-1) + nx^(n)

Except the last term, the rest is Geometric Progregssion with first term '1' and ratio 'x' with total 'n' terms

S(1-x) = 1 (1-x)/(1-x^n) + n X^n

S = 1/(1 - x^n) + nx^n/(1-x)

I hope I haven't done any mistake

Ketan
Intern
Joined: 20 Dec 2004
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20 Mar 2005, 13:38
So the final formula would be the answer? Also, where did you find this problem?
Manager
Joined: 24 Jan 2005
Posts: 217
Location: Boston

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20 Mar 2005, 14:29
I agree with ketanm.
This can also be solved by differentiatingthe series w.r.t x but I guess it'd be a longer process
Intern
Joined: 21 Jan 2013
Posts: 1
Re: 1+2x+3x^2+4x^3+.............nx^(n-1) Whats the sum of the [#permalink]

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21 Jan 2013, 14:32
In advance, I'm sorry for refreshing such an old post but I'm not quite sure If the solution ketanm had written is right.
ketanm wrote:
S(1-x) = 1 (1-x)/(1-x^n) + n X^n

The sum of geometric series is 1(1-x^n)/(1-x).
ketanm wrote:
S = 1/(1 - x^n) + nx^n/(1-x)

We can't divide by 1-x because x may equal 1.

What do u think about that?

Sry for my English, I am not a native speaker.
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7440
Location: Pune, India
Re: 1+2x+3x^2+4x^3+.............nx^(n-1) Whats the sum of the [#permalink]

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21 Jan 2013, 21:11
gmat2me2 wrote:
1+2x+3x^2+4x^3+.............nx^(n-1)

Whats the sum of the series?

First up, it is not a GMAT relevant question at all. Still, if you want to solve it for intellectual purposes,

$$S = 1+2x+3x^2+4x^3+.............nx^{n-1}$$
$$xS = x+2x^2+3x^3+4x^4+.............nx^n$$

$$S - xS = 1 + x + x^2 + x^3 + .... + x^{n-1} - nx^n$$

We know that $$1 + x + x^2 + .... + x^{n-1} = (1 - x^n)/(1-x)$$(GP with n terms and x cannot be 1)

$$S(1-x) = (1 - x^n)/(1-x) - nx^n$$
$$S = (1 - x^n)/(1-x)^2 - nx^n/(1-x)$$
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Re: 1+2x+3x^2+4x^3+.............nx^(n-1) Whats the sum of the   [#permalink] 21 Jan 2013, 21:11
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