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# [[({1/4}^1/2)({1/4}^1/2)]^1/2]^2 =

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Senior RC Moderator
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29 Aug 2019, 07:42
00:00

Difficulty:

25% (medium)

Question Stats:

85% (00:47) correct 15% (00:46) wrong based on 39 sessions

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$$(\sqrt{(\sqrt{\frac{1}{4}})(\sqrt{\frac{1}{4}})})^2$$

A. $$\frac{1}{8}$$

B. $$\frac{1}{4}$$

C. $$\sqrt{\frac{1}{4}}$$

D. $$\sqrt{\frac{1}{2}}$$

E. 1

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Senior RC Moderator
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29 Aug 2019, 07:43
Bunuel please fix this one too

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5.jpg [ 9.78 KiB | Viewed 405 times ]

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29 Aug 2019, 07:48
1
Bunuel please fix this one too

Attachment:
5.jpg

Fixed. That was a tough one.
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Senior RC Moderator
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29 Aug 2019, 07:49
You are absolutely right ! Very tough one.

Bunuel wrote:
Bunuel please fix this one too

Attachment:
5.jpg

Fixed. That was a tough one.

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29 Aug 2019, 07:57
$$(\sqrt{(\sqrt{\frac{1}{4}})(\sqrt{\frac{1}{4}})})^2$$

A. $$\frac{1}{8}$$

B. $$\frac{1}{4}$$

C. $$\sqrt{\frac{1}{4}}$$

D. $$\sqrt{\frac{1}{2}}$$

E. 1

solve bracket by bracket
$$(\sqrt{(\sqrt{\frac{1}{4}})(\sqrt{\frac{1}{4}})})^2$$
(\sqrt{\frac{1}{4}})(\sqrt{\frac{1}{4}})}
1/2*1/2; 1/4
IMO B
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29 Aug 2019, 08:00
Is it 1/4? That's what I got.
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Joined: 28 Jun 2019
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29 Aug 2019, 08:51
√1/4 *√1/4=1/4
(√1/4)^2=1/2 ^2=1/2 * 1/2=1/4
Option B

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Re: [[({1/4}^1/2)({1/4}^1/2)]^1/2]^2 =   [#permalink] 29 Aug 2019, 08:51
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