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# (1/p)^ 2 − (1/p)(1/q) =

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Intern
Joined: 28 Mar 2017
Posts: 21
(1/p)^ 2 − (1/p)(1/q) =  [#permalink]

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Updated on: 24 Mar 2019, 07:34
00:00

Difficulty:

15% (low)

Question Stats:

88% (01:25) correct 12% (01:46) wrong based on 25 sessions

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$$(\frac{1}{p})^ 2 − (\frac{1}{p})(\frac{1}{q}) =$$

(A) $$\frac{q−p}{p^2q}$$

(B) $$\frac{p−q}{p^2q}$$

(C) $$\frac{q−p}{q^2p}$$

(D) $$\frac{q−p}{p^2−pq}$$

(E) $$\frac{1}{p^2−pq}$$

Originally posted by rocketmandoman on 24 Mar 2019, 06:46.
Last edited by Bunuel on 24 Mar 2019, 07:34, edited 1 time in total.
Renamed the topic, formatted and edited the question.
NUS School Moderator
Joined: 18 Jul 2018
Posts: 1026
Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)
Re: (1/p)^ 2 − (1/p)(1/q) =  [#permalink]

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24 Mar 2019, 10:25
$$\frac{1}{p^2}-\frac{1}{pq}$$
LCM is p^2q
Then $$\frac{q-p}{p^2q}$$

Re: (1/p)^ 2 − (1/p)(1/q) =   [#permalink] 24 Mar 2019, 10:25
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