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# 1) The cost prices of 3 kinds of tea are 10$, 12$,16$per  post reply Question banks Downloads My Bookmarks Reviews Important topics Author Message Manager Joined: 13 Apr 2008 Posts: 64 Followers: 1 Kudos [?]: 12 [0], given: 0 1) The cost prices of 3 kinds of tea are 10$, 12$,16$ per [#permalink]

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14 Apr 2008, 20:21
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1) The cost prices of 3 kinds of tea are 10$, 12$,16$per bag. In what proportion should they be mixed so that the price of the mixture may be 14$ per bag?
1) 2:3:4
2) 1:2:3
3) 1:1:3
4) 1:1:2
5) 1:1:1

2) A loan is discharged in three equal installments of 2662$each. If the rate of interest is 10%, Find the amount of loan? Please explain the procedure for both. Director Joined: 10 Sep 2007 Posts: 943 Followers: 8 Kudos [?]: 302 [0], given: 0 Re: Mixture/S.I. [#permalink] ### Show Tags 14 Apr 2008, 20:48 1) Multiply first one by 10, second one by 12, and third one by 16. Add all the three and check if it is divisible by 3 or not. Only Answer 3 will satisfy the answer. 2) Total Paid = 3*2662 = 7986 X + X*10/100 = 7986 1.1X = 7986 => X = 7260 SVP Joined: 29 Aug 2007 Posts: 2476 Followers: 70 Kudos [?]: 774 [0], given: 19 Re: Mixture/S.I. [#permalink] ### Show Tags 14 Apr 2008, 20:54 Value wrote: 1) The cost prices of 3 kinds of tea are 10$, 12$,16$ per bag. In what proportion should they be mixed so that the price of the mixture may be 14$per bag? 1) 2:3:4 2) 1:2:3 3) 1:1:3 4) 1:1:2 5) 1:1:1 1) if price of the mixture is$14, then sum of the mixture must be 126. lets check whether the sum is 126 or not.
with the ratio of 2:3:4, the actual sum is (2x10 + 3x12 + 4x16) = 120. so not suff.

2) if price of the mixture is $14 and the tees are in the ratio of 1:2:3, then sum of the mixture must be 84. lets check whether the sum is 84 or not. with the ratio of 1:2:3, the actual sum is (1x10 + 2x12 + 3x16) = 82. so not suff. 3) similarly the sum must be 70. actual sum = 10x1 + 12x1 + 16x3 = 70. bingo... 4) cannot be 5) cannot be so C. Value wrote: 2) A loan is discharged in three equal installments of 2662$ each. If the rate of interest is 10%, Find the amount of loan?

Please explain the procedure for both.

assuming no advance payment, the loan amt = 2662/1.1 + 266/(1.1)^2 + 266/(1.1)^2 = 2420 + 2200 + 2000 = 6620
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Re: Mixture/S.I.   [#permalink] 14 Apr 2008, 20:54
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