GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 18 Jul 2018, 01:48

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

10 years ago, Jack was twice as old a Renee. Two years from now, Jack

Author Message
TAGS:

Hide Tags

Manager
Joined: 17 Jan 2017
Posts: 61
10 years ago, Jack was twice as old a Renee. Two years from now, Jack [#permalink]

Show Tags

07 Apr 2018, 03:01
00:00

Difficulty:

45% (medium)

Question Stats:

74% (01:42) correct 26% (03:48) wrong based on 19 sessions

HideShow timer Statistics

10 years ago, Jack was twice as old a Renee. Two years from now, Jack will be 1.5 time as old as Renee. What was the sum of the ages of Jack and Renee 5 years ago?

A. 28
B. 36
C. 46
D. 50
E. 56

Source: ExpersGlobal
Manager
Joined: 09 Aug 2017
Posts: 123
Re: 10 years ago, Jack was twice as old a Renee. Two years from now, Jack [#permalink]

Show Tags

07 Apr 2018, 03:49
j-10=2(r-10)
j+2= 3/2(r+2)
SC Moderator
Joined: 22 May 2016
Posts: 1827
10 years ago, Jack was twice as old a Renee. Two years from now, Jack [#permalink]

Show Tags

07 Apr 2018, 07:20
benejo wrote:
10 years ago, Jack was twice as old a Renee. Two years from now, Jack will be 1.5 time as old as Renee. What was the sum of the ages of Jack and Renee 5 years ago?

A. 28
B. 36
C. 46
D. 50
E. 56

Source: ExpersGlobal

Solve the first two equations. "Five years ago" can be handled at the end.

Ten years ago, Jack was twice as old as Renee:
J - 10 = 2(R -10)
J - 10 = 2R - 20
J = 2R - 10

Two years from now, Jack will be 1.5 times as old as Renee.
J + 2 = $$\frac{3}{2}$$(R + 2)
J + 2 = $$\frac{3}{2}$$R + 3

Substitute J = 2R - 10

(2R - 10) + 2 = $$\frac{3}{2}$$R + 3

2R - $$\frac{3}{2}$$R = 10 - 2 + 3
$$\frac{4}{2}$$R - $$\frac{3}{2}$$R = 11
$$\frac{1}{2}$$R = 11
R = 22

J = 2R - 10
J = 34

R + J = (22 + 34) = 46

FIVE YEARS AGO is the same.
(Do the arithmetic. There is a reason it works. If you see it, great. If not, arithmetic is simple.)
R = (22-5) = 17
J = (34-5) = 29
R + J = 46

**I left 1.5 = $$\frac{3}{2}$$ until near the end. That fraction is not hard. If you wish, at second equation, multiply all by 2 to clear the fraction: J + 2 = $$\frac{3}{2}$$(R + 2)
2J + 4 = 3(R + 2) . . .finish

_________________

In the depths of winter, I finally learned
that within me there lay an invincible summer.

10 years ago, Jack was twice as old a Renee. Two years from now, Jack   [#permalink] 07 Apr 2018, 07:20
Display posts from previous: Sort by

Events & Promotions

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.