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27 Dec 2024, 20:24
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If we assume the number of non fiction books to be x then the number of fiction books would be equal to 3x.
The total number of books would then be equal to x+3x=4x
On analyzing the options one by one.
4x cannot be equal to 15 as then the value of x would be a non integer which in this condition is not valid. Hence we can eliminate option (A)
On analysing option ( B) 4x would be equal to 20 which means 3x or fiction books would be equal to 15 & non fiction books would be equal to 5.
Out of those 15 fiction books 4/5 of them would be hardcover books which would be equal to 12 hardcover books. Out of these 12 hardcover books 3/4 are by local writers which would be equal to 9 books.
These are valid numbers in this given situation & hence the least possible value is 20.
Hence the correct answer is option (B) 20
The total number of books would then be equal to x+3x=4x
On analyzing the options one by one.
4x cannot be equal to 15 as then the value of x would be a non integer which in this condition is not valid. Hence we can eliminate option (A)
On analysing option ( B) 4x would be equal to 20 which means 3x or fiction books would be equal to 15 & non fiction books would be equal to 5.
Out of those 15 fiction books 4/5 of them would be hardcover books which would be equal to 12 hardcover books. Out of these 12 hardcover books 3/4 are by local writers which would be equal to 9 books.
These are valid numbers in this given situation & hence the least possible value is 20.
Hence the correct answer is option (B) 20
27 Dec 2024, 21:15
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A library has both fiction and nonfiction books. Of the fiction books, 4/5 are hardcover, and 3/4 of these hardcover books are authored by local writers. If the number of fiction books is three times the number of nonfiction books, what is the least total number of books in the library?
T = f + nf = nf + 3nf = 4nf => T = multiple of 4
Hard cover authored by local writers = 3/4 => multiple of 4
HC = 4/5 => multiple of 5
=> LCM of 4 & 5 is 20
=> Ans B
T = f + nf = nf + 3nf = 4nf => T = multiple of 4
Hard cover authored by local writers = 3/4 => multiple of 4
HC = 4/5 => multiple of 5
=> LCM of 4 & 5 is 20
=> Ans B
27 Dec 2024, 21:53
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Let number of nonfiction books = n
fiction books = 3n
total books = n + 3n = 4n
hardcover = (3n) 4/5 = 12n/5
local writers = (3/4)(12n/5) = 9n/5
For all values to be integers, n must be a multiple of 5 (which is n = 5)
Total books = 4n = 4*5 = 20
fiction books = 3n
total books = n + 3n = 4n
hardcover = (3n) 4/5 = 12n/5
local writers = (3/4)(12n/5) = 9n/5
For all values to be integers, n must be a multiple of 5 (which is n = 5)
Total books = 4n = 4*5 = 20
