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Re: 17^3 + 17^4 = [#permalink]
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dave13 wrote:
Bunuel wrote:
SOLUTION

17^3 + 17^4 =

(A) 17^7
(B) 17^3*18
(C) 17^6*18
(D) 2*17^3 + 17
(E) 2*17^3 - 17

\(17^3 + 17^4 =17^3(1+17)=17^3*18\).

Answer: B.


Hi Bunuel, how do you call this rule when from this \(17^3 + 17^4\) you get this \(17^3(1+17)\) ? please explain in two or three words :)


We are factoring out common term 17^3 from 17^3 + 17*17^3 to get 17^3(1+17).
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Re: 17^3 + 17^4 = [#permalink]
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Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

\(17^3 + 17^4\) =

(A) 17^7
(B) 17^3*18
(C) 17^6*18
(D) 2*17^3 + 17
(E) 2*17^3 - 17


\(17^3 + 17^4\) has the same format as \(x^3 + x^4\), which we can factor as follows: \(x^3(1 + x)\)
The same applies to the given expression.
\(17^3 + 17^4=17^3(1 + 17)\)
\(=(17^3)(18)\)

Answer: B

Cheers,
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Re: 17^3 + 17^4 = [#permalink]
Bunuel wrote:

17^3 + 17^4 =

(A) 17^7
(B) 17^3*18
(C) 17^6*18
(D) 2*17^3 + 17
(E) 2*17^3 - 17

\(17^3 + 17^4\)

Or, \(17^3( 1 + 17)\)

Or, \(17^3*18\), thus answer will be (B)
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Re: 17^3 + 17^4 = [#permalink]
WRT Question
17^3+17^4
= 17^3(common) [1+17]
=17^3*18
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Re: 17^3 + 17^4 = [#permalink]
Expert Reply
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

17^3 + 17^4 =

(A) 17^7
(B) 17^3*18
(C) 17^6*18
(D) 2*17^3 + 17
(E) 2*17^3 - 17


17^3 + 17^4 = 17^3(1 + 17) = 17^3 x 18

Answer: B
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Re: 17^3 + 17^4 = [#permalink]
Bunuel wrote:
SOLUTION

17^3 + 17^4 =

(A) 17^7
(B) 17^3*18
(C) 17^6*18
(D) 2*17^3 + 17
(E) 2*17^3 - 17

\(17^3 + 17^4 =17^3(1+17)=17^3*18\).

Answer: B.


Hi Bunuel, how do you call this rule when from this \(17^3 + 17^4\) you get this \(17^3(1+17)\) ? please explain in two or three words :)
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Re: 17^3 + 17^4 = [#permalink]
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

17^3 + 17^4 =

(A) 17^7
(B) 17^3*18
(C) 17^6*18
(D) 2*17^3 + 17
(E) 2*17^3 - 17


17^3 + 17^4 = 17^3 (1+ 17) = 17^3 (18)

Answer: B
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Re: 17^3 + 17^4 = [#permalink]
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

17^3 + 17^4 =

(A) 17^7
(B) 17^3*18
(C) 17^6*18
(D) 2*17^3 + 17
(E) 2*17^3 - 17

Problem Solving
Question: 108
Category: Arithmetic Exponents
Page: 75
Difficulty: 550


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17^3 + 17^4

Or, 17^3(1 + 17)

17^3 * 18

(B)
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Re: 17^3 + 17^4 = [#permalink]
Can someone please explain why the answer still cannot be A?
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Re: 17^3 + 17^4 = [#permalink]
meganmcl1 wrote:
Can someone please explain why the answer still cannot be A?


When you multiply powers with the same base you add the exponents. When you add powers with the same base you can only take common factor.
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Re: 17^3 + 17^4 = [#permalink]
andreagonzalez2k
Thank you so much!
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Re: 17^3 + 17^4 = [#permalink]
Expert Reply
\(17^3 + 17^4 = 17^3(1 + 17) = 17^3(18)\)

Answer B
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Re: 17^3 + 17^4 = [#permalink]
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Re: 17^3 + 17^4 = [#permalink]
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