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# 2^2)-1))((2^2)+1))((2^4)+1))((2^8)+1))= A) (2^16)-1 B)

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Director
Joined: 06 Feb 2006
Posts: 898
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2^2)-1))((2^2)+1))((2^4)+1))((2^8)+1))= A) (2^16)-1 B) [#permalink]

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26 Nov 2006, 05:35
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Difficulty:

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Question Stats:

100% (02:08) correct 0% (00:00) wrong based on 2 sessions

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((2^2)-1))((2^2)+1))((2^4)+1))((2^8)+1))=

A) (2^16)-1
B) (2^16)+1
C) (2^32)-1
D) (2^128)-1
E) 2^16((2^16)-1)
Director
Joined: 06 Feb 2006
Posts: 898
Followers: 3

Kudos [?]: 112 [0], given: 0

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26 Nov 2006, 06:34
I did apply this formula but somehow managed to make a mistake... maybe rushed a bit too hard...
Yes now it works fine.

OA is A
26 Nov 2006, 06:34
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# 2^2)-1))((2^2)+1))((2^4)+1))((2^8)+1))= A) (2^16)-1 B)

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