It is currently 19 Nov 2017, 19:28

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# 2^64)^(2^64) = 2^P What does P equal to? This looks

Author Message
Intern
Joined: 06 Jan 2006
Posts: 23

Kudos [?]: [0], given: 0

Location: Illinois
2^64)^(2^64) = 2^P What does P equal to? This looks [#permalink]

### Show Tags

17 Feb 2006, 22:45
1
This post was
BOOKMARKED
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

(2^64)^(2^64) = 2^P
What does P equal to?

This looks like a really simple problem. Too bad I remember absolutely nothing from my math days...I do remember a rule that lets you move the power to the front of the equation? Or am I mistaken on that?
Can anyone refresh that concept with me if I remembered it correctly?

Thanks!

P.S. By the way, I don't have the OA...
_________________

Taking the GMAT in five days. CRAM TIME! Should have started preparing sooner

Kudos [?]: [0], given: 0

Intern
Joined: 06 Jan 2006
Posts: 23

Kudos [?]: [0], given: 0

Location: Illinois

### Show Tags

17 Feb 2006, 22:54
lol, oops I plugged in some numbers and finally figured it out. The rule was that you could multiply the first power with the base of the second power, in this case you could multiply the first 64 with the second (2^64) on the left side of the equation.....
_________________

Taking the GMAT in five days. CRAM TIME! Should have started preparing sooner

Kudos [?]: [0], given: 0

VP
Joined: 29 Dec 2005
Posts: 1337

Kudos [?]: 69 [0], given: 0

Re: PS - two to the powers of... [#permalink]

### Show Tags

18 Feb 2006, 07:42
cattalk wrote:
(2^64)^(2^64) = 2^P, What does P equal to?

This looks like a really simple problem. Too bad I remember absolutely nothing from my math days...I do remember a rule that lets you move the power to the front of the equation? Or am I mistaken on that?
Can anyone refresh that concept with me if I remembered it correctly?

Thanks! P.S. By the way, I don't have the OA...

(2^3)^(2^3) = 2^P
(2x2x2)^(2x2x2) = 2^P
(2)^(2x2x2) x (2)^(2x2x2) x (2)^(2x2x2) = 2^P
(2)^(8) x (2)^(8) x (2)^(8) = 2^P
(2)^(8+8+8) = 2^P
(2)^(24) = 2^P

therefore, p = 24 = 3 (2^3)

similarly (2^64)^(2^64) = 2^P
p = 64 x (2^64). i will check, if any.

Kudos [?]: 69 [0], given: 0

Intern
Joined: 16 Aug 2005
Posts: 37

Kudos [?]: 2 [0], given: 0

### Show Tags

18 Feb 2006, 07:58
(x^y)^z= x^(y*z)

Hence:
(2^64)^(2^64)
=2^(64*(2^64))
=2^((2^6)*(2^64))
=2^(2^(6+64))
=2^(2^70)

P=2^70

Kudos [?]: 2 [0], given: 0

18 Feb 2006, 07:58
Display posts from previous: Sort by