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2 men and 3 women are lined up in a row. What is the number of cases w

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Math Revolution GMAT Instructor
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2 men and 3 women are lined up in a row. What is the number of cases w  [#permalink]

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New post 26 May 2016, 16:24
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Question Stats:

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2 men and 3 women are lined up in a row. What is the number of cases where they stand with each other in turn? (The number of cases in which men (or women) do not stand next to each other)

A. 12
B. 15
C. 18
D. 21
E. 24

*An answer will be posted in 2 days.

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Re: 2 men and 3 women are lined up in a row. What is the number of cases w  [#permalink]

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New post 26 May 2016, 18:31
MathRevolution wrote:
2 men and 3 women are lined up in a row. What is the number of cases where they stand with each other in turn? (The number of cases in which men (or women) do not stand next to each other)

A. 12
B. 15
C. 18
D. 21
E. 24

*An answer will be posted in 2 days.


First place the 3 women in 3! ways....
then place 2 men in the two gaps created in between women in 2! ways..
total = \(3!*2! = 12\) ways
A
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Re: 2 men and 3 women are lined up in a row. What is the number of cases w  [#permalink]

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New post 27 May 2016, 01:01
MathRevolution wrote:
2 men and 3 women are lined up in a row. What is the number of cases where they stand with each other in turn? (The number of cases in which men (or women) do not stand next to each other)

A. 12
B. 15
C. 18
D. 21
E. 24

*An answer will be posted in 2 days.



First arrange 3 women. 3 women can be arranged in 3 places in 3! ways. Now

W Blank W BlankW

we have to fill the two blanks with 2 men. We can arrange 2 persons in 2 places in 2! ways.

3! * 2! = 12 ways.

A is the answer
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Re: 2 men and 3 women are lined up in a row. What is the number of cases w  [#permalink]

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New post 29 May 2016, 19:45
The list should be WMWMW. Hence, from women 3! And men 2!, we get (3!)(2!)=12. Therefore, the correct answer is A.
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2 men and 3 women are lined up in a row. What is the number of cases w  [#permalink]

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New post 02 Dec 2018, 14:13
MathRevolution wrote:
2 men and 3 women are lined up in a row. What is the number of cases where they stand with each other in turn? (The number of cases in which men (or women) do not stand next to each other)

A. 12
B. 15
C. 18
D. 21
E. 24

*An answer will be posted in 2 days.


total possibilities=5!=120
required possibility is w,m,w,m,w
probability=3/5*2/4*2/3*1/2*1=1/10
1/10*120=12 cases
A
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2 men and 3 women are lined up in a row. What is the number of cases w &nbs [#permalink] 02 Dec 2018, 14:13
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