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# 2^x - 2^x-2 = 3(2^13) a) 9 b) 11 c) 13 d) 15 e) 17

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Joined: 21 Sep 2006
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2^x - 2^x-2 = 3(2^13) a) 9 b) 11 c) 13 d) 15 e) 17 [#permalink]

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14 Oct 2006, 16:23
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

2^x - 2^x-2 = 3(2^13)

a) 9

b) 11

c) 13

d) 15

e) 17
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Joined: 30 Aug 2006
Posts: 374
Followers: 3

Kudos [?]: 68 [0], given: 0

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14 Oct 2006, 16:42
15, took a while but i think i'm going to bed now!

2^x - 2^x-2 = 3(2^13)

2^x(1 - 2^-2) = 3(2^13)
2^x(1 - 1/4) = 3(2^13)
2^x(3/4) = 3(2^13)
2^x = 3(2^13)*4/3
2^x = (2^13)4
2^x = (2^13)2^2
2^x = 2^15

a) 9

b) 11

c) 13

d) 15

e) 17
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14 Oct 2006, 17:25
londonluddite wrote:
15, took a while but i think i'm going to bed now!

2^x - 2^x-2 = 3(2^13)

2^x(1 - 2^-2) = 3(2^13)
2^x(1 - 1/4) = 3(2^13)
2^x(3/4) = 3(2^13)
2^x = 3(2^13)*4/3
2^x = (2^13)4
2^x = (2^13)2^2
2^x = 2^15

a) 9

b) 11

c) 13

d) 15

e) 17

Perfect! Thank you.
14 Oct 2006, 17:25
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