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# 2^X)*(3^Y)*(5^Z) is the greatest positive divisor of (8!)^4.

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Manager
Joined: 25 May 2003
Posts: 54

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07 Jun 2003, 00:44
well, other option is to take 7^4 into account

7^4=2^11.229.....

therefore 2^x=2^39.229

therefore XYZ equals about 39.229*8*4

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Founder
Joined: 04 Dec 2002
Posts: 15456

Kudos [?]: 27974 [0], given: 5052

Location: United States (WA)
GMAT 1: 750 Q49 V42

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07 Jun 2003, 00:49
skoper wrote:
well, other option is to take 7^4 into account

7^4=2^11.229.....

therefore 2^x=2^39.229

therefore XYZ equals about 39.229*8*4

I agree if X is not an integer.

A good point!

-=-

Kudos [?]: 27974 [0], given: 5052

Manager
Joined: 25 May 2003
Posts: 54

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08 Jun 2003, 02:06

Kudos [?]: 3 [0], given: 0

08 Jun 2003, 02:06

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# 2^X)*(3^Y)*(5^Z) is the greatest positive divisor of (8!)^4.

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