Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 27 May 2017, 21:23

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# 2^X)*(3^Y)*(5^Z) is the greatest positive divisor of (8!)^4.

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Director
Joined: 05 Jan 2008
Posts: 690
Followers: 5

Kudos [?]: 472 [0], given: 0

2^X)*(3^Y)*(5^Z) is the greatest positive divisor of (8!)^4. [#permalink]

### Show Tags

26 May 2008, 02:04
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

(2^X)*(3^Y)*(5^Z) is the greatest positive divisor of (8!)^4. the value of x+y+z=?
_________________

Persistence+Patience+Persistence+Patience=G...O...A...L

CEO
Joined: 17 Nov 2007
Posts: 3586
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 575

Kudos [?]: 3982 [0], given: 360

Re: PS: X+Y+Z [#permalink]

### Show Tags

26 May 2008, 02:11
$$(8!)^4=(8*7*6*5*4*3*2)^4=(2^3*7*2*3*5*2^2*3*2)^4=(2^7*7*3^2*5)^4=2^{28}*3^8*5^4*7$$

x+y+z=28+8+4=40
_________________

HOT! GMAT TOOLKIT 2 (iOS) / GMAT TOOLKIT (Android) - The OFFICIAL GMAT CLUB PREP APP, a must-have app especially if you aim at 700+ | PrepGame

Director
Joined: 05 Jan 2008
Posts: 690
Followers: 5

Kudos [?]: 472 [0], given: 0

Re: PS: X+Y+Z [#permalink]

### Show Tags

26 May 2008, 02:18
yup it is
_________________

Persistence+Patience+Persistence+Patience=G...O...A...L

SVP
Joined: 28 Dec 2005
Posts: 1561
Followers: 3

Kudos [?]: 158 [0], given: 2

Re: PS: X+Y+Z [#permalink]

### Show Tags

26 May 2008, 04:39
with walker ... 40 for me as well.

Start off with 8! , which we know is 8x7x6x5x4x3x2x1 ... we can write 8 as 2x2x2, 6 as 2x3, 4 as 2x2 ... you end up with 2^7*7*3^2*5 ... and now apply the power of 4 to get 2*28*7^4*3^8*5^4 ... add up the exponents to get 28+8+4=40
VP
Joined: 18 May 2008
Posts: 1265
Followers: 17

Kudos [?]: 447 [0], given: 0

Re: PS: X+Y+Z [#permalink]

### Show Tags

26 May 2008, 06:15
Nice explanation!
Re: PS: X+Y+Z   [#permalink] 26 May 2008, 06:15
Display posts from previous: Sort by

# 2^X)*(3^Y)*(5^Z) is the greatest positive divisor of (8!)^4.

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.