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# (2xy^2)*(7x^3y^3) =

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Math Expert
Joined: 02 Sep 2009
Posts: 59615

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25 Oct 2018, 03:52
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Difficulty:

5% (low)

Question Stats:

88% (00:33) correct 12% (01:11) wrong based on 74 sessions

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$$(2xy^2)*(7x^3y^3) =$$

A. $$9x^4y^5$$

B. $$14x^4y^5$$

C. $$9x^3y^6$$

D. $$14x^3y^6$$

E. $$14x^6y^6$$

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25 Oct 2018, 04:51
1
=> 2*7 * x^(1+3) y^(2+3)
=14x^4 y^5 (B)
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25 Oct 2018, 07:41
Bunuel wrote:
$$(2xy^2)*(7x^3y^3) =$$

A. $$9x^4y^5$$

B. $$14x^4y^5$$

C. $$9x^3y^6$$

D. $$14x^3y^6$$

E. $$14x^6y^6$$

$$(2xy^2)*(7x^3y^3) =$$

$$= 2*7*x^{1+3}*y^{2+3}$$

$$= 14*x^4*y^5$$; Answer must be (B)
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25 Oct 2018, 07:56
Bunuel wrote:
$$(2xy^2)*(7x^3y^3) =$$

A. $$9x^4y^5$$

B. $$14x^4y^5$$

C. $$9x^3y^6$$

D. $$14x^3y^6$$

E. $$14x^6y^6$$

solution: 14x^4y^5

hence B
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30 Oct 2018, 11:19
Bunuel wrote:
$$(2xy^2)*(7x^3y^3) =$$

A. $$9x^4y^5$$

B. $$14x^4y^5$$

C. $$9x^3y^6$$

D. $$14x^3y^6$$

E. $$14x^6y^6$$

Multiplying the coefficients and adding the respective exponents of x and y, we have:

14x^4*y^5

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Re: (2xy^2)*(7x^3y^3) =   [#permalink] 30 Oct 2018, 11:19
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