Bunuel wrote:

\(\frac{3^{14}–3^{12}}{6^3}=\)

A. 3^8

B. 3^9

C. 3^10

D. 3^12

E. 3^14

\(\frac{3^{14}–3^{12}}{6^3}=\)

\(\frac{3^{12}(3^2–1)}{3^3*2^3}=\)

\(\frac{3^{12}(8)}{3^3*(8)}=3^{12-3}=3^9\)

Answer B

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In the depths of winter, I finally learned

that within me there lay an invincible summer.

-- Albert Camus, "Return to Tipasa"