GMAT Question of the Day: Daily via email | Daily via Instagram New to GMAT Club? Watch this Video

It is currently 19 Feb 2020, 08:49

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

3/8 of all students at Social High are in all three of the

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
CrackVerbal Quant Expert
User avatar
G
Joined: 12 Apr 2019
Posts: 385
Re: 3/8 of all students at Social High are in all three of the  [#permalink]

Show Tags

New post 19 Nov 2019, 22:13
In this question on overlapping sets, let the total number of students be 80, since 80 is a common multiple of the denominators of the fractions given. It’s neither too small that it will end up giving fractions nor too large that you have to spend time on calculations.

Keeping 80 as the number of students in Social High, we can draw a Venn diagram like the one below:

Attachment:
20th Nov 2019 - Reply 1.jpg
20th Nov 2019 - Reply 1.jpg [ 34.81 KiB | Viewed 40 times ]


Note that the region outside the circles is ZERO since the question says that every student is in at least one club. This is crucial information; always be on the lookout for such statements in an Overlapping sets question because they make your life easy.

3/8th of 80 i.e. 30 are in all the three clubs. The respective number of students in the Albanian, Bardic and Checkmate sets are 40, 50 and 60 respectively.
If we add these values, we get 150. But, this 150 includes repetition of certain regions – a, b and c appear twice; 30 appears thrice. So, we will have to remove a, b and c once and 30 twice. If we do that, we should obtain 80 since that is the actual total number of students in the school.

Therefore, 150 – a – b – c – 60 = 80. Solving this, we get a+b+c = 10. a+b+c represents the number of people who belong to exactly two clubs. Hence, the required fraction = 10/80 = 1/8.
The correct answer option is A.

Hope that helps!
_________________
GMAT Club Bot
Re: 3/8 of all students at Social High are in all three of the   [#permalink] 19 Nov 2019, 22:13

Go to page   Previous    1   2   [ 21 posts ] 

Display posts from previous: Sort by

3/8 of all students at Social High are in all three of the

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  





Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne