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# 3 kinds of ice cream, chocolate, vanilla, and strawberry are

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Intern
Joined: 29 Jul 2005
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3 kinds of ice cream, chocolate, vanilla, and strawberry are [#permalink]

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24 Aug 2005, 21:31
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0% (00:00) correct 0% (00:00) wrong based on 3 sessions

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3 kinds of ice cream, chocolate, vanilla, and strawberry are to be selected. In a survey of 60 people about the preference of the ice cream, 3/5 will put the vanilla on the last position, 1/3 put the vanilla ahead of the chocolate, and 1/10 put the vanilla ahead of strawberry. How many people will put the strawberry on the first position?

1. 2
2. 3
3. 4
4. 5
5. 6

SVP
Joined: 05 Apr 2005
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25 Aug 2005, 06:31
Priti wrote:
3 kinds of ice cream, chocolate, vanilla, and strawberry are to be selected. In a survey of 60 people about the preference of the ice cream, 3/5 will put the vanilla on the last position, 1/3 put the vanilla ahead of the chocolate, and 1/10 put the vanilla ahead of strawberry. How many people will put the strawberry on the first position?

1. 2
2. 3
3. 4
4. 5
5. 6

hmmm. pretty tough...

btw, is the question correct?????
Senior Manager
Joined: 04 May 2005
Posts: 279
Location: CA, USA
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25 Aug 2005, 08:55
I have many possible scenarios:

20 put strawberry at position 1
the same is true for 21 , 22, 23 strawberries at position 1

it satisfies:
Quote:
3/5 will put the vanilla on the last position,

36 vanila at 3rd place

Quote:
1/3 put the vanilla ahead of the chocolate,

20 vanila ahead of chocolate ( s v c, v s c)
Quote:
and 1/10 put the vanilla ahead of strawberry.

6 ( v c s, or c v s)

do we miss a condition that defines direct connection between strawberry and cholate directly ?
Intern
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25 Aug 2005, 11:24
I followed a similar approach

did the following:

1. SVC
2. VSC
3. SCV
4. CSV
5. VCS
6. CVS

Tried forming Eqns after this, but couldn't proceed.
Manager
Joined: 06 Aug 2005
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25 Aug 2005, 12:12
Is this a genuine question ?
I don't think it is well-founded, and the English is appalling.

We know,

CSV + SCV = 36
SVC + VSC + VCS = 20
CVS + VSC + VCS = 6
And sum of all 6 possibilities = 60
So VSC + VCS = 2
SVC = 18
CVS = 4

But we cannot split CSV + SCV up.
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04 Sep 2005, 22:26
Agree with all,
there are many possible variants. I think it the question is wrongly given
04 Sep 2005, 22:26
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