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39,897*0.0096/198.76 is approximately

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Bunuel
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39,897*0.0096/198.76 is approximately [#permalink] 39,897*0.0096/198.76 is approximately   03 Jul 2016, 11:31
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69% (01:02) correct 31% (01:08) wrong based on 2732 sessions
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\(\frac{39,897*0.0096}{198.76}\) is approximately

A) 0.02
B) 0.2
C) 2
D) 20
E) 200
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C
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BrentGMATPrepNow
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Re: 39,897*0.0096/198.76 is approximately [#permalink] 39,897*0.0096/198.76 is approximately   03 Jul 2016, 11:49
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Bunuel
39,897*0.0096/198.76 is approximately

A) 0.02
B) 0.2
C) 2
D) 20
E) 200
First scan the answer choices.
Since they're spread apart, we can estimate AGGRESSIVELY (for more on this strategy, see the video below )
(39,897)(0.0096)/198.76 ≈ (40,000)(0.01)/(200)
≈ (400)/(200)
≈ 2
Answer:
Show Spoiler
C



Cheers,
Brent
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rohitrawat9990
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39,897*0.0096/198.76 is approximately [#permalink] 39,897*0.0096/198.76 is approximately   Updated on: 03 Jul 2016, 11:55
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40000*.01/200
400/200
2
correct


Sent from my iPhone using GMAT Club Forum mobile app

Originally posted by rohitrawat9990 on 03 Jul 2016, 11:47.
Last edited by rohitrawat9990 on 03 Jul 2016, 11:55, edited 2 times in total.
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generis
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39,897*0.0096/198.76 is approximately [#permalink] 39,897*0.0096/198.76 is approximately   04 Mar 2018, 20:38
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Bunuel
\(\frac{39,897*0.0096}{198.76}\) is approximately

A) 0.02
B) 0.2
C) 2
D) 20
E) 200
\(\frac{39,897*0.0096}{198.76}\)
If moving decimal points isn't your first choice, round the numbers and use powers of 10:

40,000 = 4 * 10\(^4\)
.01 = 1 * 10\(^{-2}\)
200 = 2 * 10\(^2\)

\(\frac{(4*10^4)*(1*10^{-2})}{(2*10^2)}\)

\(\frac{(4*10^4)}{(2*10^2)*(1*10^2)}\)

\(\frac{4*10^4}{2*10^{(2+2)}}\)

\(\frac{4*10^4}{2*10^4} = 2\)

Answer C
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39,897*0.0096/198.76 is approximately [#permalink] 39,897*0.0096/198.76 is approximately   23 Mar 2018, 11:30
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dave13
Bunuel
\(\frac{39,897*0.0096}{198.76}\) is approximately

A) 0.02
B) 0.2
C) 2
D) 20
E) 200

:-) when we round 0.0096 ...aren't we getting 0.001 ? :)

if so then then 40000 * 0.001 = 40

so 40/200 = 0.2

why is the answer C ? :?
Yikes - I had a bad typo in there. Good catch. +1

Round .0096 to .01
(We look at only one digit to the right: .009 = .01)

Now, 40,000*.01 = 400
Better? :-)
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Re: 39,897*0.0096/198.76 is approximately [#permalink] 39,897*0.0096/198.76 is approximately   23 Mar 2018, 03:50
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Bunuel
\(\frac{39,897*0.0096}{198.76}\) is approximately

A) 0.02
B) 0.2
C) 2
D) 20
E) 200

:-) when we round 0.0096 ...aren't we getting 0.001 ? :)

if so then then 40000 * 0.001 = 40

so 40/200 = 0.2

why is the answer C ? :?
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Re: 39,897*0.0096/198.76 is approximately [#permalink] 39,897*0.0096/198.76 is approximately   04 Jul 2016, 00:11
2

40000*100/200*10000=2
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Re: 39,897*0.0096/198.76 is approximately [#permalink] 39,897*0.0096/198.76 is approximately   27 Oct 2016, 14:16
[39,897 x (96/10000)]/(19876/100) = [40,000 x 100]/[100 x 20,000] = 2
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Re: 39,897*0.0096/198.76 is approximately [#permalink] 39,897*0.0096/198.76 is approximately   27 Feb 2018, 10:08
Expert Reply
Bunuel
\(\frac{39,897*0.0096}{198.76}\) is approximately

A) 0.02
B) 0.2
C) 2
D) 20
E) 200

Approximating the given expression, we have:

(40,000 x 0.01)/200 = 400/200 = 2

Answer: C
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Re: 39,897*0.0096/198.76 is approximately [#permalink] 39,897*0.0096/198.76 is approximately   22 Oct 2018, 10:51
Bunuel
\(\frac{39,897*0.0096}{198.76}\) is approximately

A) 0.02
B) 0.2
C) 2
D) 20
E) 200

Round 39,897 to 40,000 and 0.0096 to 0.01. Also round 198.76 to 200

\(\frac{40,000}{200} = 200 * 0.01 = 200 * \frac{1}{100} = 2\)

Answer choice C
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Re: 39,897*0.0096/198.76 is approximately [#permalink] 39,897*0.0096/198.76 is approximately   07 Jan 2019, 09:54
remove decimal part and do simple calculation. you will get correct answer.
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Re: 39,897*0.0096/198.76 is approximately [#permalink] 39,897*0.0096/198.76 is approximately   07 Oct 2020, 20:23
when it's written approximately - good that you convert to round figures = (40,000 * 0.01) / 200 = 400/200 = 2 ans
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Re: 39,897*0.0096/198.76 is approximately [#permalink] 39,897*0.0096/198.76 is approximately   08 Apr 2024, 00:48
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Re: 39,897*0.0096/198.76 is approximately [#permalink]
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