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# (3x + 2) (2x - 5) = ax² + kx + n . What is the value of a - n + k ?

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Re: (3x + 2) (2x - 5) = ax² + kx + n . What is the value of a - n + k ? [#permalink]
Bunuel wrote:
(3x + 2) (2x - 5) = ax^2 + kx + n . What is the value of a - n + k ?

A. 5
B. 8
C. 9
D. 10
E. 11

Simplify LHS..
$$(3x+2)(2x-5) = 6x^2-11x-10 = ax^2-n+k$$...
equate the coefficients...
a=6 ; k = -11 and n = -10..
so $$a-n+k = 6-(-10)+(-11) = 6+10-11 = 5$$
A
Re: (3x + 2) (2x - 5) = ax² + kx + n . What is the value of a - n + k ? [#permalink]
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