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(4^8 - 3^8)/(4^4 + 3^4)=

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Math Expert
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Joined: 02 Sep 2009
Posts: 52906
(4^8 - 3^8)/(4^4 + 3^4)=  [#permalink]

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New post 16 Aug 2017, 01:05
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

87% (01:25) correct 13% (01:43) wrong based on 103 sessions

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Intern
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Joined: 22 Apr 2015
Posts: 26
WE: Business Development (Internet and New Media)
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Re: (4^8 - 3^8)/(4^4 + 3^4)=  [#permalink]

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New post 16 Aug 2017, 02:31
2
\(\frac{4^8-3^8}{4^4+3^4}\)
= \(\frac{{4^4}^{2}-{3^4}^{2}}{4^4+3^4}\)
= \(\frac{(4^4+3^4)(4^4-3^4)}{(4^4+3^4)}\)
=\(4^4-3^4\)
=256-81
=175 8-)
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(4^8 - 3^8)/(4^4 + 3^4)=  [#permalink]

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New post 16 Aug 2017, 05:55
1
1
Bunuel wrote:
\(\frac{{4^8 - 3^8}}{{4^4 + 3^4}}=\)

A. 7
B. 25
C. 156
D. 175
E. 216

Can be solved using the formula : \(a^2 -b^2 = (a+b)(a-b)\)

\(\frac{{4^8 - 3^8}}{{4^4 + 3^4}}\)

\(\frac{(4^4 - 3^4)(4^4+3^4)}{(4^4 + 3^4)}\)

Cancelling \((4^4+3^4\)); we get;

\((4^4 - 3^4)\)

\((4^2-3^2)(4^2 + 3^2)\)

\((4-3)(4+3)(4^2 + 3^2)\)

\((1)(7)(16 + 9)\)

\((7)(25) = 175\)

Answer (D)...
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Re: (4^8 - 3^8)/(4^4 + 3^4)=  [#permalink]

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New post 07 Oct 2018, 22:38
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: (4^8 - 3^8)/(4^4 + 3^4)=   [#permalink] 07 Oct 2018, 22:38
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