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# (4^5 + 4^3)/4^2

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Joined: 31 Oct 2013
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Concentration: Accounting, Finance
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(4^5 + 4^3)/4^2  [#permalink]

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Updated on: 22 Jun 2018, 21:25
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Difficulty:

15% (low)

Question Stats:

81% (00:36) correct 19% (00:58) wrong based on 44 sessions

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$$\frac{(4^5+4^3)}{4^2} =$$

A. $$4^2$$

B. $$4^3$$

C. $$4^3+4$$

D. $$4^4$$

E. $$4^6$$

Originally posted by KSBGC on 22 Jun 2018, 13:45.
Last edited by Bunuel on 22 Jun 2018, 21:25, edited 2 times in total.
Edited the question
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Re: (4^5 + 4^3)/4^2  [#permalink]

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22 Jun 2018, 15:11
$$4^5$$+$$4^3$$/$$4^2$$ =

Hi,

Please correct the errot, the equation has to be $$(4^5$$+$$4^3$$)/$$4^2$$
Otherwise only $$4^3$$ is devided by $$4^2$$
Math Expert
Joined: 02 Aug 2009
Posts: 8584
Re: (4^5 + 4^3)/4^2  [#permalink]

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22 Jun 2018, 19:14
selim wrote:
($$4^5$$+$$4^3$$)/$$4^2$$ =

A.$$4^2$$
B. $$4^3$$
C.$$4^3$$+4
D. $$4^4$$
E.$$4^6$$

($$4^5$$+$$4^3$$)/$$4^2$$ =$$\frac{4^3(4^2+1)}{4^2}$$
=>$$4(4^2+1)=4^3+4$$

OR
$$\frac{(4^5+4^3)}{4^2}=\frac{4^5}{4^2}+\frac{4^3}{4^2}=4^{5-2}-4^{3-2}=4^3+4$$

C
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Re: (4^5 + 4^3)/4^2  [#permalink]

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23 Jun 2018, 04:53
Top Contributor
selim wrote:
$$\frac{(4^5+4^3)}{4^2} =$$

A. $$4^2$$

B. $$4^3$$

C. $$4^3+4$$

D. $$4^4$$

E. $$4^6$$

Often-tested rule: (a + b)/c = a/c + b/c

So, (4^5 + 4^3)/4^2 = (4^5)/4^2 + (4^3)/4^2
= 4^3 + 4^1
= 4^3 + 4

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Re: (4^5 + 4^3)/4^2   [#permalink] 23 Jun 2018, 04:53

# (4^5 + 4^3)/4^2

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