It is currently 19 Nov 2017, 11:32

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# 4 professors and 6 students are being considered for

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Director
Joined: 10 Feb 2006
Posts: 654

Kudos [?]: 634 [0], given: 0

4 professors and 6 students are being considered for [#permalink]

### Show Tags

06 Jun 2007, 21:34
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

4 professors and 6 students are being considered for membership on a supervisory committee which must consist of 3 people. In how many ways can this committee be formed if it has to include at least 1 professor ?
_________________
GMAT the final frontie!!!.
_________________

GMAT the final frontie!!!.

Kudos [?]: 634 [0], given: 0

Manager
Joined: 17 Oct 2006
Posts: 52

Kudos [?]: 2 [0], given: 0

### Show Tags

06 Jun 2007, 22:02
Since a committee containing prof. A& B is similar to committee containing prof. B&A so it means that order doesn't matter and therefore it is a combinations problem.
Now, this question has three possible committe compositions, 1) with 1 prof and 2 studets, 2) with 2 prof and 1 students and 3) with 3 prof. and no students in the committee.
SO working the maths now
1 prof from 4 can be chosen in 4C1 wasy and 2 students from 6 studnets can be chosen in 6C2 ways. Similarly setting up maths for other two combinations, we get
(4C1*6C2)+(4C2*6C1)+(4C3)
=(4!/3!*6!/2!*4!)+(4!/2!*2!*6!/5!)+(4!/3!)
=(4*15)+(6*6)+(4)
=60+36+4
=100 Ans
Ciao

Kudos [?]: 2 [0], given: 0

06 Jun 2007, 22:02
Display posts from previous: Sort by

# 4 professors and 6 students are being considered for

 post reply Question banks Downloads My Bookmarks Reviews Important topics

Moderator: chetan2u

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.