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(49∗18)+(24∗84)−(56∗9)21(49∗18)+(24∗84)−(56∗9)/21

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Math Expert
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(49∗18)+(24∗84)−(56∗9)21(49∗18)+(24∗84)−(56∗9)/21  [#permalink]

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New post 23 Jan 2020, 00:51
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A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

86% (02:09) correct 14% (02:16) wrong based on 28 sessions

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GMAT 1: 740 Q51 V39
(49∗18)+(24∗84)−(56∗9)21(49∗18)+(24∗84)−(56∗9)/21  [#permalink]

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New post 23 Jan 2020, 01:40
Solution:

\(\frac{{(49∗18)+(24∗84)−(56∗9)}}{21}\)

= \(\frac{{7*3*(7∗6)+3*7*(8∗12)−7*3*(8∗3)}}{21}\)

= \(\frac{[7*3{(7∗6)+(8∗12)−(8∗3)}]}{(7*3)}\)

= \((7∗6)+(8∗12)−(8∗3)\)

= \(42+96−24\)

= 114

Answer C



Alternate approach:

\(\frac{{(49∗18)+(24∗84)−(56∗9)}}{21}\)

=~ \(\frac{{(50∗20)+(25∗80)−(55∗10)}}{20}\)

= \(\frac{{1000+2000−550}}{20}\)

= \(\frac{2450}{20}\)

= 112.5 (approximate value)

Answer C since it is the only option having a 3-digit number
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(49∗18)+(24∗84)−(56∗9)21(49∗18)+(24∗84)−(56∗9)/21   [#permalink] 23 Jan 2020, 01:40

(49∗18)+(24∗84)−(56∗9)21(49∗18)+(24∗84)−(56∗9)/21

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