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# 4x > 3y? 1 4x > 2y 2. x/y <1

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Manager
Joined: 31 Jan 2005
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4x > 3y? 1 4x > 2y 2. x/y <1 [#permalink]

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01 Feb 2006, 02:02
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4x > 3y?
1 4x > 2y
2. x/y <1
_________________

"Nothing is Impossible"

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Director
Joined: 17 Dec 2005
Posts: 544

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Location: Germany
Re: DS INEQUALITIES !!! - BEAST !!! [#permalink]

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01 Feb 2006, 02:55
jinesh wrote:
4x > 3y?
1 4x > 2y
2. x/y <1

1)
2x>y

so x>=0 and y<2x

If y is negative than 4x>3y is true

If y is, for instance, 3 and x=2 than 4x>3y is not true

2)

x/y<1

so y>x or y<0 or x<=0

insufficient

1+2)

x>=0 and y<0

C it is, but indeed it's confusing maybe I've made a mistake

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VP
Joined: 21 Sep 2003
Posts: 1057

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Location: USA
Re: DS INEQUALITIES !!! - BEAST !!! [#permalink]

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01 Feb 2006, 09:27
jinesh wrote:
4x > 3y?
1 4x > 2y
2. x/y <1

I think it is E.

Is 4x>3y?

1) 4x>2y => x > y/2

For (x,y) = (7,8)
x>y/2 is True
4x>3y is True (4x=28, 3y =24)

For (x,y) = (5,8)
x>y/2 is True
4x>3y is False (4x=20, 3y=24) INSUFF.

2) x/y< 1
For (x,y) = (7,8)
x/y < 1 True
4x>3y is True

For (x,y) = (5/8)
x/y<1 is True
4x>3y is False

Combining (1) & (2), doesn't give anything more.
For two values (5,8) and (7,8) which satisfy both conditions, 4x<3y can be True or False

Hence E.
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Director
Joined: 17 Dec 2005
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01 Feb 2006, 09:32
you're right girish

My last conclusion is wrong; y needs not to be negative

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Director
Joined: 26 Sep 2005
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Location: Munich,Germany
Re: DS INEQUALITIES !!! - BEAST !!! [#permalink]

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08 Feb 2006, 07:00
jinesh wrote:
4x > 3y?
1 4x > 2y
2. x/y <1

question: is x>3y/4 ?

stmt 1, 4x>2y = x>2y/4 , if x > 2y/4 does not mean its also greater than 3y/4, therefore insuff

stmt 2, x/y<1, x/y > 3/4 or x< 3/4, hence insuff

together, x/y >1/2 and x/y<1 again is insuff, Hence E

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Senior Manager
Joined: 05 Jan 2006
Posts: 381

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08 Feb 2006, 09:48
4x>3y = x>.75y

1) 4x>2y => x>.5y =>can not say x>.75 y Insufficient
2) x/y<1 => x < y can not say x>.75y

Combining both to gather

x>.5y
x<y

.5y < x < y can not conclude x>.75y!

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08 Feb 2006, 09:48
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# 4x > 3y? 1 4x > 2y 2. x/y <1

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