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# 50 tricky questions

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Director
Joined: 24 Aug 2007
Posts: 923
WE 1: 3.5 yrs IT
WE 2: 2.5 yrs Retail chain

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23 Jun 2010, 00:42
5
KUDOS
Not just verbal kudos.
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Manager
Joined: 11 Jun 2010
Posts: 64

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23 Jun 2010, 19:23
Great, Thanks for sharing
Senior Manager
Status: Time to step up the tempo
Joined: 24 Jun 2010
Posts: 403
Location: Milky way
Schools: ISB, Tepper - CMU, Chicago Booth, LSB

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15 Jul 2010, 18:04
Thanks for posting these questions... +1 from me....
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Intern
Joined: 17 Jul 2010
Posts: 21
Location: Tbilisi, Georgia

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28 Jul 2010, 02:45
although I missed most of the questions still it's very helpful source!!

thanks
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Intern
Joined: 30 Jul 2010
Posts: 1
Schools: HBS

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31 Jul 2010, 02:44
hey guys - the answer for the first MATH problem is 159 and so the solution is wrong in pdf...

here is why:

from the solution in arithmetic progression you got n=79

so the d=2, first term = 2 and so the last term would be a+(n-1)d = 2+(79-1)2 = 159

cherio...
Manager
Joined: 27 Jun 2010
Posts: 55
Location: India
WE 1: 1 Year Research & Development
WE 2: 7.5 Years IT Consultant

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31 Jul 2010, 03:15
I am doing these questions but they do not look like GMAT questions.
Is it beneficial to to solve these questions?
Intern
Joined: 02 Sep 2009
Posts: 16

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06 Aug 2010, 05:46
Thanks for sharing.
Manager
Joined: 20 Jul 2010
Posts: 77

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06 Aug 2010, 11:07
Intern
Joined: 27 Nov 2009
Posts: 2

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18 Aug 2010, 22:28
Intern
Joined: 10 Aug 2010
Posts: 1

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19 Aug 2010, 03:33
Thanks for the questions..Kudos.

By the way, I don't agree with the answer to question 1.

You said n=79, but if n=79 then we would have:
2+4+6+8+....+78 = 2(1+2+3+4+....+39) = 2 (39*40/2) = 39*40.

Ithink the answer should be 159.

2+4+6+...+158 = 2(1+2+3+..+79) = 2(79*80/2) = 79*80.

---
Well spotted.
The 'n' in the Arithmetic Progression equation should be replaced with (n-1)/2. Because when you have every other number in a continous series, the total no of even numbers is (n-1)/2 when the nth term is odd.
Manager
Joined: 31 Mar 2010
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20 Aug 2010, 21:32
That's great thanks!
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GMAT: 720 Q47 V41 / TOEFL iBT: 118

Intern
Joined: 10 Jul 2010
Posts: 1

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24 Aug 2010, 19:08
thanks..kudos to you
Intern
Joined: 17 Aug 2010
Posts: 7

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27 Aug 2010, 01:49
Thanks for sharing!
Manager
Status: Brainstorming.
Joined: 16 Feb 2010
Posts: 211
Location: United States
GMAT 1: 540 Q47 V19
GMAT 2: 610 Q46 V28
GPA: 3.86
WE: Programming (Computer Software)

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27 Aug 2010, 03:23
Manager
Joined: 16 Aug 2009
Posts: 221

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03 Sep 2010, 01:02
mohanksri wrote:
hey guys - the answer for the first MATH problem is 159 and so the solution is wrong in pdf...

here is why:

from the solution in arithmetic progression you got n=79

so the d=2, first term = 2 and so the last term would be a+(n-1)d = 2+(79-1)2 = 159

cherio...

Was wondering the same..
Good spot !
VP
Status: Current Student
Joined: 24 Aug 2010
Posts: 1344
Location: United States
GMAT 1: 710 Q48 V40
WE: Sales (Consumer Products)

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13 Sep 2010, 11:50
Is this where we can discuss the solutions to the problems? I'm looking at problem two and don't quite understand a couple of things.

1) Do we have to add the two equations: x+y+z=50 & 6x-2y-z=192 or can we subtract them? Why or why not?
2) Where does the assumption that y can't be 1 or 2 come from. Please explain.

Liz
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Intern
Joined: 20 Jul 2010
Posts: 49

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19 Oct 2010, 08:59
Thanks for sharing
Manager
Joined: 13 Jan 2009
Posts: 170

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20 Oct 2010, 03:11
Great questions. Thanks for sharing!
Manager
Joined: 06 Sep 2010
Posts: 111

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29 Jul 2011, 22:21
Thanks for sharing!!!
Manager
Joined: 27 Apr 2008
Posts: 191

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02 Aug 2011, 13:03
How are you supposed to actually learn how to solve these questions? I could spend an hour trying to solve some of the questions and even that I will probably still be stumped....is there a good way to learn the tricks to solve these toughies?
Re: 50 tricky questions   [#permalink] 02 Aug 2011, 13:03

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