coolkl wrote:
S-2)
S-1) I thought Mean = Median so equidistance elements. So the sequence of elements can be starting 58 or any number SD will remain same. This is because adding constant C, Standard Deviation doesnot change. But the answer says only B. Cant I infer the set as Equidistance ? Bunnel or Any one kindly help ?
Hi,
There are 16 numbers with mean in middle of 72&74 or 73..
Let's see the statements..
1. the Mean number of students is equal to the median number of students in the the 10 classes.
mean=median does not necessarily mean equidistant..Example..
Five numbers with average 74..
1) 70,72,74,76,78.... Equidistant
2) 66,72,74,78,80... Now these are not Equidistant..
So the standard deviation will be different for both above examples
Hence insufficient
2. number of students in any class is more than 63 and the avg. number of students in 10 classes is same as average of the above list
This tells us that the lowest number can be 64 and average is 73..
Only possibility is the numbers are 64,66,68,70,72 and corresponding numbers will be 74,76,78,80,82
Hence the standard deviation will always be same
Sufficient
B
Sir can you explain how you solved for statement 2? It is said that the number of students in each class is not equal to the numbers in the above list......and since possibilities are it can start from 65 and end at 87........it is impossible to distribute 10 numbers between 65 and 87 with mean 73........Least possible 10 numbers are...65,67,69,71,73,75,77,79,81 and 83......in this case average is 74??