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# (6^2 - 4^2)/2^2 =

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Math Expert
Joined: 02 Sep 2009
Posts: 53798

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07 Mar 2019, 00:02
00:00

Difficulty:

15% (low)

Question Stats:

100% (00:30) correct 0% (00:00) wrong based on 20 sessions

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$$\frac{6^2 - 4^2}{2^2} =$$

(A) 1

(B) 2

(C) 3

(D) 4

(E) 5

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Math Expert
Joined: 02 Aug 2009
Posts: 7437
Re: (6^2 - 4^2)/2^2 =  [#permalink]

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07 Mar 2019, 09:00
Bunuel wrote:
$$\frac{6^2 - 4^2}{2^2} =$$

(A) 1

(B) 2

(C) 3

(D) 4

(E) 5

This contains very small number and each square can be easily calculated..
$$\frac{6^2 - 4^2}{2^2}$$=$$\frac{36 - 16}{4} =5$$

If say the terms were big, then we should be able to take out the denominator from the numerator..
$$\frac{6^2 - 4^2}{2^2}$$=$$\frac{(2*3)^2 - (2*2)^2}{2^2}$$=$$\frac{2^23^2 - 2^22^2}{2^2} =\frac{2^2(3^2 - 2^2)}{2^2}=3^2-2^2=9-4=5$$

E
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1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html
4) Base while finding % increase and % decrease : https://gmatclub.com/forum/percentage-increase-decrease-what-should-be-the-denominator-287528.html

GMAT Expert

Re: (6^2 - 4^2)/2^2 =   [#permalink] 07 Mar 2019, 09:00
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