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(6^2 - 4^2)/2^2 =

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Joined: 02 Sep 2009
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(6^2 - 4^2)/2^2 =  [#permalink]

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New post 06 Mar 2019, 23:02
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

90% (00:35) correct 10% (00:35) wrong based on 42 sessions

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Re: (6^2 - 4^2)/2^2 =  [#permalink]

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New post 07 Mar 2019, 08:00
Bunuel wrote:
\(\frac{6^2 - 4^2}{2^2} =\)

(A) 1

(B) 2

(C) 3

(D) 4

(E) 5


This contains very small number and each square can be easily calculated..
\(\frac{6^2 - 4^2}{2^2}\)=\(\frac{36 - 16}{4} =5\)

If say the terms were big, then we should be able to take out the denominator from the numerator..
\(\frac{6^2 - 4^2}{2^2}\)=\(\frac{(2*3)^2 - (2*2)^2}{2^2}\)=\(\frac{2^23^2 - 2^22^2}{2^2} =\frac{2^2(3^2 - 2^2)}{2^2}=3^2-2^2=9-4=5\)


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Re: (6^2 - 4^2)/2^2 =   [#permalink] 07 Mar 2019, 08:00

(6^2 - 4^2)/2^2 =

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