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(7^9 + 7^8)/8 =

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(7^9 + 7^8)/8 =  [#permalink]

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New post Updated on: 08 Jul 2019, 00:16
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A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

100% (00:20) correct 0% (00:00) wrong based on 11 sessions

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Originally posted by Bunuel on 01 Jun 2017, 11:13.
Last edited by SajjadAhmad on 08 Jul 2019, 00:16, edited 1 time in total.
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Re: (7^9 + 7^8)/8 =  [#permalink]

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New post 01 Jun 2017, 11:33
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(7^9+7^8)/8=(7^8)(7+1)/8=7^8

Is there a formatting issue? Should (D) 78 be (D) 7^8?
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Re: (7^9 + 7^8)/8 =  [#permalink]

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New post 01 Jun 2017, 11:49
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Top Contributor
Bunuel wrote:
\(\frac{7^9 + 7^8}{8} =\)

(A) 1/8
(B) 7/8
(C) 77/8
(D) 78
(E) 79


\(\frac{7^9 + 7^8}{8} = \frac{7^8(7^1 + 1)}{8}\)

\(= \frac{7^8(7 + 1)}{8}\)

\(= \frac{7^8(8)}{8}\)

\(= 7^8\)

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Re: (7^9 + 7^8)/8 =  [#permalink]

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New post 01 Jun 2017, 11:51
1
Bunuel wrote:
\(\frac{7^9 + 7^8}{8} =\)

(A) 1/8
(B) 7/8
(C) 77/8
(D) 78
(E) 79



I think there is a formatting problem. The answer should be 7^8.
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Re: (7^9 + 7^8)/8 =  [#permalink]

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New post 01 Jun 2017, 11:54
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Re: (7^9 + 7^8)/8 =   [#permalink] 01 Jun 2017, 11:54

(7^9 + 7^8)/8 =

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