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Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each [#permalink]
RupamPaul13 wrote:
Total no of possible arrangements: 8P7=40320
Now no of arrangements where at least 1 person is there between A and F = Total possible arrangements- No of arrangements where A and F are together.

No. of Arrangements whereA and F are together = 7P6=10080

So the final answer is 40320-10080=30240(Option D)


RupamPaul13
see highlighted part , but we have 8 seats to make 7 such options sit ; so wont it be 8P7 ways...
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Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each [#permalink]
Archit3110 wrote:
RupamPaul13 wrote:
Total no of possible arrangements: 8P7=40320
Now no of arrangements where at least 1 person is there between A and F = Total possible arrangements- No of arrangements where A and F are together.

No. of Arrangements whereA and F are together = 7P6=10080

So the final answer is 40320-10080=30240(Option D)


RupamPaul13
see highlighted part , but we have 8 seats to make 7 such options sit ; so wont it be 8P7 ways...



Sorry my bad, it should be 2* 7P6 as AF is taken as a single entity and they will occupy 2 seats. So 6 entity in 7 entities (seats) and AF can be arranged in 2 ways so 7P6
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Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each [#permalink]
Total arrangements - Arrangements where A and F are together
Total - 8 Seats and 7 people = 8P7 = 720*7*8 = 4320
Arrangements where A and F are together = 7 seats and 6 people = 7P6*2 (As A and F can interchange) = 720*7*2 = 1080.
So 30240 arrangements Option D
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Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each [#permalink]
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Arvind42 wrote:
Total arrangements - Arrangements where A and F are together
Total - 8 Seats and 7 people = 8P7 = 720*7*8 = 4320
Arrangements where A and F are together = 7 seats and 6 people = 7P6*2 (As A and F can interchange) = 720*7*2 = 1080.
So 30240 arrangements Option D


Arvind42 why have you mentioned 7 seats and 6 people where as it should be 8 seats and 6 people...
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Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each [#permalink]
Archit3110 wrote:
Arvind42 wrote:
Total arrangements - Arrangements where A and F are together
Total - 8 Seats and 7 people = 8P7 = 720*7*8 = 4320
Arrangements where A and F are together = 7 seats and 6 people = 7P6*2 (As A and F can interchange) = 720*7*2 = 1080.
So 30240 arrangements Option D


Arvind42 why have you mentioned 7 seats and 6 people where as it should be 8 seats and 6 people...


Archit3110 But won't A and F require 2 seats to sit. So i reduced 1 from both the seats and people.
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Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each [#permalink]
Arvind42 wrote:
Archit3110 wrote:
Arvind42 wrote:
Total arrangements - Arrangements where A and F are together
Total - 8 Seats and 7 people = 8P7 = 720*7*8 = 4320
Arrangements where A and F are together = 7 seats and 6 people = 7P6*2 (As A and F can interchange) = 720*7*2 = 1080.
So 30240 arrangements Option D


Arvind42
when taking case of A&F together cant we take in 8P6 ways ?
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Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each [#permalink]
Quote:
Arvind42
when taking case of A&F together cant we take in 8P6 ways ?


Archit3110. I don't think so. Cause we join A and F together for computational purposes (still we multiply the end result by 2 as we recognize that they can interchange between themselves). So the seat count should also be reduced to that extent.
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Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each [#permalink]
Arvind42 wrote:
Quote:
Arvind42
when taking case of A&F together cant we take in 8P6 ways ?


Archit3110. I don't think so. Cause we join A and F together for computational purposes (still we multiply the end result by 2 as we recognize that they can interchange between themselves). So the seat count should also be reduced to that extent.


Arvind42
OK i understood ...
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Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each [#permalink]
Archit3110 wrote:
Bunuel wrote:
7 people, A, B, C, D, E, F and H, go to a movie and sit next to each other in 8 adjacent seats in the front row of the theatre. In how many different arrangements will there be at least one person between A and F?

A. 5,040
B. 10,080
C. 20,160
D. 30,240
E. 35.280


atleast = total ways - together
total ways ; 8*7*6*5*4*3*2 ; 40320
and together ; 7*6*5*4*3*2 ; 5040 ; AF can interchange so 5040*2; 10080
40320-10080 ; 30240
IMO D



Hi Archit3110

You have negated the possibilities where A and F are sitting together but will this still not include the cases where there is an empty seat in between A and F? Whereas the question mentions there must be a person between A and F.

Please explain

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Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each [#permalink]
Expert Reply
But there can be an empty seat b/w A and F in certain cases instead of a person.

How do we incorporate that into our solution ?
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Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each [#permalink]
GmatMinion wrote:
But there can be an empty seat b/w A and F in certain cases instead of a person.

How do we incorporate that into our solution ?


Bunuel chetan2u VeritasKarishma

I have the same query as quoted. Can you please provide an explanation?

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Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each [#permalink]
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firas92 wrote:
GmatMinion wrote:
But there can be an empty seat b/w A and F in certain cases instead of a person.

How do we incorporate that into our solution ?


Bunuel chetan2u VeritasKarishma

I have the same query as quoted. Can you please provide an explanation?

Posted from my mobile device



The question is flawed, in both wording and answer..

Wording.. 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each other in 8 adjacent seats in the front row of the theatre.
This means all are seating next to each other, so you can have V,_,_,_,_,_,_,_ or _,_,_,_,_,_,_,V ------- so 7!*2

But ofcourse question means
7 people, A, B, C, D, E, F and H, go to a movie and sit on 8 adjacent seats in the front row of the theatre.

Now, when this is what the question means..
at least one person between A and F implies even when there is a seat empty has to be subtracted ---- so we have to subtract (A,_,F) and 5 seats so 6!*2 from the final answer
Thus answer becomes 8!-7!*2-6!*2

But if the question was supposed to have answer as 8!-7*2!, then wordings should have been
at least one person chair between A and F
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Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next to each [#permalink]
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firas92 wrote:
GmatMinion wrote:
But there can be an empty seat b/w A and F in certain cases instead of a person.

How do we incorporate that into our solution ?


Bunuel chetan2u VeritasKarishma

I have the same query as quoted. Can you please provide an explanation?

Posted from my mobile device


This question is a part of a series of examples in one of my blog posts to explain arrangements under constraints. There are no options given and it is not a standalone question. Hence, I have not given a lot of thought to the exact wording as long as the intent of the question is clear as in how it is different from the previous.
Request you to check out the entire post to get the context and the solution in detail: https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2011/1 ... ts-part-i/

The intent of the question is that 7 people need to sit on 8 seats in the front row. In the solution, you do have to incorporate that there might be an empty seat between A and F and the answer given is 8! – 2*7! – 2*6! (which is not in the options - 28,800)

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