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8√4n=(4√2)^8, n=?

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8√4n=(4√2)^8, n=?  [#permalink]

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New post 11 Jul 2016, 00:49
00:00
A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

56% (01:50) correct 44% (02:07) wrong based on 58 sessions

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8√4n=(4√2)^8, n=?
A. 4^8
B. 4^10
C. 4^12
D. 4^16
E. 4^32

*An answer will be posted in 2 days

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Re: 8√4n=(4√2)^8, n=?  [#permalink]

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New post 11 Jul 2016, 03:01
MathRevolution wrote:
8√4n=(4√2)^8, n=?
A. 4^8
B. 4^10
C. 4^12
D. 4^16
E. 4^32

*An answer will be posted in 2 days



Given 8√4n = \((4√2)^8\) and asked to find n.

8 ( √4n ) = \((4√2)^8\)

Now dealing RHS.
=> \(4^8\) \((√2)^8\)
=> \(4^8\) \((2)^4\)

Now
8 ( √4n ) = \(4^8\) \((2)^4\)
( √4n ) = \(4^8\) (2) ( Cancelling 8 on both LHS ad RHS) ( Here square root will get rid when square it)

Now squaring on both sides.
4n = 4^16 (4) ( Cancelling 4 on both sides).

n = 4^16.

Thus D is the correct option.
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Re: 8√4n=(4√2)^8, n=?  [#permalink]

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New post 12 Jul 2016, 18:51
The correct answer is D.
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Re: 8√4n=(4√2)^8, n=?  [#permalink]

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New post 13 Jul 2016, 04:27
I'm getting 4^8 as an answer.


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Re: 8√4n=(4√2)^8, n=?  [#permalink]

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New post 13 Jul 2016, 06:51
rikingajjar wrote:
I'm getting 4^8 as an answer.


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The question is √4 * n and not √(4n). Try solving again now :)
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Re: 8√4n=(4√2)^8, n=?  [#permalink]

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New post 13 Jul 2016, 06:52
haha okay! mobile app has some issues with root thing :)


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8√4n=(4√2)^8, n=?  [#permalink]

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New post 17 Jan 2019, 03:08
What am I missing:

\(8*\sqrt{4}*n=4^8*\sqrt{2}^8\)

\(\implies\) \(\sqrt{4}*n=4^8*2\)

\(\implies\) \(2n=4^8*2\)

\(\implies\) \(n=4^8\)
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Re: 8√4n=(4√2)^8, n=?  [#permalink]

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New post 17 Jan 2019, 03:15
Divyadisha wrote:
rikingajjar wrote:
I'm getting 4^8 as an answer.


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The question is √4 * n and not √(4n). Try solving again now :)


That is incorrect: it is in fact √(4n) not √4 * n
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Re: 8√4n=(4√2)^8, n=?   [#permalink] 17 Jan 2019, 03:15
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