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81^(1/4) + 64^(1/3) + 24^(1/2) =

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Math Expert
Joined: 02 Sep 2009
Posts: 55266
81^(1/4) + 64^(1/3) + 24^(1/2) =  [#permalink]

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06 Apr 2018, 05:17
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Difficulty:

15% (low)

Question Stats:

86% (00:54) correct 14% (01:16) wrong based on 89 sessions

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$$\sqrt[4]{81} + \sqrt[3]{64} + \sqrt{24} =$$

A. $$7 + 2\sqrt{6}$$

B. $$9 + \sqrt{6}$$

C. $$7 + 4\sqrt{6}$$

D. $$7\sqrt{6}$$

E. $$9\sqrt{6}$$

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81^(1/4) + 64^(1/3) + 24^(1/2) =  [#permalink]

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06 Apr 2018, 05:40
Bunuel wrote:
$$\sqrt[4]{81} + \sqrt[3]{64} + \sqrt{24} =$$

A. $$7 + 2\sqrt{6}$$

B. $$9 + \sqrt{6}$$

C. $$7 + 4\sqrt{6}$$

D. $$7\sqrt{6}$$

E. $$9\sqrt{6}$$

$$\sqrt[4]{81} = 3$$

$$\sqrt[3]{64} = 4$$

$$\sqrt{24} = 2\sqrt{6}$$

Hence A
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Resource: GMATPrep RCs With Solution
81^(1/4) + 64^(1/3) + 24^(1/2) =   [#permalink] 06 Apr 2018, 05:40
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