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A 2year certificate of deposit is purchased for K dollars. [#permalink]
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30 Nov 2005, 10:46
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64% (01:03) correct 36% (00:58) wrong based on 370 sessions
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A 2year certificate of deposit is purchased for K dollars. If the certificate earns interest at a n annual rate of 6 percent compound quarterly, which of the following represents the value, in dollars, of the certificate at the end of 2 years? A. k(1.06)^2 B. k(1.06)^8 C. k(1.015)^2 D. k(1.015)^8 E. k(1.03)^4
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Senior Manager
Joined: 11 Nov 2005
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B
k(1+0.06)^8
2 years = 8 times interest if paid quaterly



Director
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I am getting answer as A.
But there is definitely an easier method than what I have done



Senior Manager
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I also got B
since it pays quarterly we take 4*2 (no of years) = 8



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D)...compund interest is: initial amount*(1+interest/x)^(time*x), where x is the number of times compunded annually
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Director
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should we all memorize this compound interest fomula? or is it not necessary?



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joemama142000 wrote: should we all memorize this compound interest fomula? or is it not necessary?
I would memorise it. A variation of it is used various contexts(eg money growing by 10% every year, mixture pbs etc)
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duttsit wrote: christoph wrote: D)...compund interest is: initial amount*(1+interest/x)^(time*x), where x is the number of times compunded annually Agree. k *(1 + 0.06/4) ^ (2 * 4)
annual interest rate (r) = 6%
term (n) = 2
value of k at the end of 2 yrs, if compounded annually=k(1+r)^n=k(1+0.06)^2
quaterly int. rate (r) = 1.5%
term (n) = 2x4 = 8
value of k at the end of 2 yrs, if compounded qtrly =k(1+r)^n=k(1+0.015)^8
so D.



Director
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joemama142000 wrote: should we all memorize this compound interest fomula? or is it not necessary?
It is necessary.
I've taken the test yesterday, and one of the math questions required calculation of compound interest. Obviously, the formular was not given.
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Got D as well. Just remember that with compound interest the # of compoundings must be multiplied to the # of years> 4*2=8.
Between B and D, B fails to divide the interest rate (6%) by the compound (4). Therefore, it cannot be 1.06.
(D) by POE



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Re: PS Compount interest [#permalink]
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02 Dec 2005, 04:19
I think its good to know the formula for CI. The formula is
A=P(1+r/100)^n, Where P is the priniciple, R is the rate of interest, and n is the number of years.
In our case P =K, r = 6 and n = 8 (Since the interest is compounded quareterly, and for 2 years there are 8 quarters).
So it is K(1+6/100)^8
K(1.06)^8



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Re: PS Compount interest [#permalink]
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02 Dec 2005, 07:03
krisrini wrote: I think its good to know the formula for CI. The formula is A=P(1+r/100)^n, Where P is the priniciple, R is the rate of interest, and n is the number of years. In our case P =K, r = 6 and n = 8 (Since the interest is compounded quareterly, and for 2 years there are 8 quarters).
So it is K(1+6/100)^8 K(1.06)^8
I think your formula is missing a few factors. We also must divide the interest rate by the # of compoundings per year (n) and multiply n by the number of years (y):
FV (future value)
P (principle)
r (interest rate expressed in decimal form)
n (number of compoundings)
t (time, in years)
FV=P(1+r/n)^t*n



Director
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christoph wrote: D)...compund interest is: initial amount*(1+interest/x)^(time*x), where x is the number of times compunded annually
If this is the formula for Compund Interest, we get interest as
k(1.015)^8
But we are asked the amount after two years isnt it.
Please can someone correct me where I am wrong.



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remgeo wrote: christoph wrote: D)...compund interest is: initial amount*(1+interest/x)^(time*x), where x is the number of times compunded annually If this is the formula for Compund Interest, we get interest as k(1.015)^8 But we are asked the amount after two years isnt it. Please can someone correct me where I am wrong.
k is the initial amount. so end amount at the end of 2 years = k (1.015)^8



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Re: PS Compount interest [#permalink]
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27 May 2007, 16:16
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GMATT73 wrote: We also must divide the interest rate by the # of compoundings per year (n) and multiply n by the number of years (y):
FV (future value) P (principle) r (interest rate expressed in decimal form) n (number of compoundings) t (time, in years)
FV=P(1+r/n)^t*n
yes this is the correct answer. its a very simple question.
FV=P(1+r/n)^t*n
k [1+ (6/4)] ^ (4*2)
k [1+ (.015)] ^8
therefore D



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Re: A 2year certificate of deposit is purchased for K dollars. [#permalink]
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18 Jan 2015, 07:01
joemama142000 wrote: A 2year certificate of deposit is purchased for K dollars. If the certificate earns interest at a n annual rate of 6 percent compound quarterly, which of the following represents the value, in dollars, of the certificate at the end of 2 years?
A. k(1.06)^2 B. k(1.06)^8 C. k(1.015)^2 D. k(1.015)^8 E. k(1.03)^4 Annual Rate of interest= 6% Quaterly rate of interest= 6/4% = 1.5% Now, periods of compounding in 2 years= 8 (8 quarters) Thus k(1.015)^8 Answer: D



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Re: A 2year certificate of deposit is purchased for K dollars. [#permalink]
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05 Oct 2017, 06:34
I picked up initially on the fact that there are 2 years (or 8 quarters), but fell for the ANNUAL RATE of 1.06 because i forgot to divide that .06 interest rate by 4 quarters. Subtle.




Re: A 2year certificate of deposit is purchased for K dollars.
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05 Oct 2017, 06:34






