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Re: A and B are nonzero integers, is A < 5B? [#permalink]
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A and B are nonzero integers, is A < 5B?

(1) A/B < 5
If a=4, b=1 yes
If a=-4 and b=-5 no
Insufficient

(2) B > 3
No info given on A
Insufficient

Combined, 5b will always be larger than a/b as b is greater than 3 and a cannot take on a value greater than 5×greater than 3
Sufficient

Answer: C
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Re: A and B are nonzero integers, is A < 5B? [#permalink]
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The answer is C

using both we get b>3 so A<5b
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Re: A and B are nonzero integers, is A < 5B? [#permalink]
Bunuel wrote:
A and B are nonzero integers, is A < 5B?

(1) A/B < 5
(2) B > 3

Kudos for a correct solution.


Statement 1:
Doesn't tell about the sign of A or B,so we cannot answer the question.
INSUFFICIENT

Statement 2:
Doesn't tell anything about A.
INSUFFICIENT

Combining statements 1 and 2.
from statement 2 we know that B is positive and greater than 3.
If we combine this with statement 1, we know for sure that 5B is greater than A as A can only take values for which A/B<5
SUFFICIENT

Answer:- C
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A and B are nonzero integers, is A < 5B? [#permalink]
Bunuel wrote:
A and B are nonzero integers, is A < 5B?

(1) A/B < 5
(2) B > 3

Kudos for a correct solution.


Without number picking:

(1)A/B < 5

\(\frac{A}{B}-5<0\)

\(\frac{A-5B}{B}<0\)

So (A-5B) AND B have different signs
Case 1: B>0 then A-5b<0
Case 2: B<0 then A-5B>0
Insuff

(2)B>2.
Noting about a,insuff.

Using (1) and (2):
From (2) We know B>0 so A-5b<0
Hence A>5b
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A and B are nonzero integers, is A < 5B? [#permalink]
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