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# a and b are positive integers. What is the remainder of of

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Senior Manager
Joined: 30 May 2005
Posts: 373

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a and b are positive integers. What is the remainder of of [#permalink]

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25 Jun 2005, 19:53
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a and b are positive integers. What is the remainder of of (6*10^b + a - 1)/3 ?

S1) a = 2

S2) b = 5

Kudos [?]: 12 [0], given: 0

Senior Manager
Joined: 17 Apr 2005
Posts: 372

Kudos [?]: 30 [0], given: 0

Location: India

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25 Jun 2005, 20:14
AJB77 wrote:
a and b are positive integers. What is the remainder of of (6*10^b + a - 1)/3 ?

S1) a = 2

S2) b = 5

A would suffice. The remainder is 1.

B insufficient.

HMTG.

Kudos [?]: 30 [0], given: 0

Director
Joined: 18 Feb 2005
Posts: 668

Kudos [?]: 6 [0], given: 0

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25 Jun 2005, 20:15
It is A

(6*10^b + a - 1)/3 = 2*10^b + (a - 1)/3

So if we know a thats enough

Kudos [?]: 6 [0], given: 0

25 Jun 2005, 20:15
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# a and b are positive integers. What is the remainder of of

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