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A and B ran, at their respective constant rates, a race of 480 m. In

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G
Joined: 07 Dec 2014
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Re: A and B ran, at their respective constant rates, a race of 480 m. In [#permalink]

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New post 27 Jan 2016, 15:37
let t=A's time in seconds for each heat, assuming consistent speed of A
B's speed in heat 1=432/t+6 m/s
B's speed in heat 2=336/(t-2} m/s
assuming consistent speed of B, 432/(t+6)=336/(t-2)
t=30 seconds
B's speed=432/36=336/28=12 m/s
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Re: A and B ran, at their respective constant rates, a race of 480 m. In [#permalink]

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New post 08 Jul 2017, 08:29
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case 1:, B has been given 48m headstart; A won by 6 seconds.
case 2, B is given headstart of 144m; B won by 2 sec

So, B went on from losing to winning & we know this happened for time difference of 8 seconds (from loosing by 6 sec to winning by 2 seconds), This happened because B traveled 144-48 = 96m more in first case.
Now B traveled 96m in 8 sec and hence, speed of B = 96/8 = 12m/s

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Re: A and B ran, at their respective constant rates, a race of 480 m. In [#permalink]

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New post 20 Jan 2018, 04:32
A goes 480m in t seconds. In t seconds B goes 432-6x where x is his rate. In the next race b goes 336 in t-2 seconds. So in two seconds b goes (432-6x)-336=96-6x meters. He would also go 2x meters every two seconds. 96-6x=2x so x =12m/s

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Re: A and B ran, at their respective constant rates, a race of 480 m. In   [#permalink] 20 Jan 2018, 04:32

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A and B ran, at their respective constant rates, a race of 480 m. In

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