GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 20 Oct 2019, 07:00 GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  A and B start running simultaneously. A r

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

Hide Tags

Manager  G
Joined: 03 Nov 2018
Posts: 60
Location: India
Schools: LBS '21
GMAT 1: 580 Q44 V28 GMAT 2: 580 Q44 V28 GPA: 3.44
A and B start running simultaneously. A r  [#permalink]

Show Tags

3 00:00

Difficulty:   55% (hard)

Question Stats: 62% (03:20) correct 38% (02:50) wrong based on 29 sessions

HideShow timer Statistics

A and B start running simultaneously. A runs from point P to point Q and B from point Q to point P. AA's speed is 6/5 of B's speed. After crossing B, if A takes 5/2 hr to reach Q, how much time does BB take to reach PP after crossing A?
A.3 hr 6 min
B.3 hr 16 min
C.3 hr 26 min
D.3 hr 36 min
E 3 hr
Senior PS Moderator V
Joined: 26 Feb 2016
Posts: 3335
Location: India
GPA: 3.12
A and B start running simultaneously. A r  [#permalink]

Show Tags

1
2
Attachment: Diagram.png [ 4.14 KiB | Viewed 1190 times ]

Let's assume arbitrary values for speeds of A and B: B - 50 kmph and A - 60 kmph

If the total distance from P to Q is x km, the point at which A and B make contact is 5/2 * 60 or 150 kms from Q.
The total distance of B from point P is x - 150. The time taken for A and B to reach the point is the same.

Equating the times we get $$\frac{150 - x}{60} = \frac{150}{50}$$ -> $$x = 330$$

The total distance that B travels towards P after the point of contact is 180km.

Therefore, B will take $$\frac{180}{50} * 60 = 216$$minutes or 3 hour, 36 minutes(Option C) to reach P after crossing A.
_________________
You've got what it takes, but it will take everything you've got
Manager  B
Joined: 27 Oct 2017
Posts: 72
Re: A and B start running simultaneously. A r  [#permalink]

Show Tags

pushpitkc wrote:
Attachment:
Diagram.png

Let's assume arbitrary values for speeds of A and B: B - 50 kmph and A - 60 kmph

If the total distance from P to Q is x km, the point at which A and B make contact is 5/2 * 60 or 150 kms from Q.
The total distance of B from point P is x - 150. The time taken for A and B to reach the point is the same.

Equating the times we get $$\frac{150 - x}{60} = \frac{150}{50}$$ -> $$x = 330$$

The total distance that B travels towards P after the point of contact is 180km.

Therefore, B will take $$\frac{180}{50} * 60 = 216$$minutes or 3 hour, 36 minutes(Option C) to reach P after crossing A.

Maybe I am missing something, but can you please tell me why the time taken for A and B to reach the point is the same? For both A and B we assumed different speeds.
Senior PS Moderator V
Joined: 26 Feb 2016
Posts: 3335
Location: India
GPA: 3.12
A and B start running simultaneously. A r  [#permalink]

Show Tags

arorni wrote:
pushpitkc wrote:
Attachment:
Diagram.png

Let's assume arbitrary values for speeds of A and B: B - 50 kmph and A - 60 kmph

If the total distance from P to Q is x km, the point at which A and B make contact is 5/2 * 60 or 150 kms from Q.
The total distance of B from point P is x - 150. The time taken for A and B to reach the point is the same.

Equating the times we get $$\frac{150 - x}{60} = \frac{150}{50}$$ -> $$x = 330$$

The total distance that B travels towards P after the point of contact is 180km.

Therefore, B will take $$\frac{180}{50} * 60 = 216$$minutes or 3 hour, 36 minutes(Option C) to reach P after crossing A.

Maybe I am missing something, but can you please tell me why the time taken for A and B to reach the point is the same? For both A and B we assumed different speeds.

Hey arorni

Since both of them start simultaneously, the point at which they meet has to be the same.

Hope that helps
_________________
You've got what it takes, but it will take everything you've got
Manager  B
Joined: 27 Oct 2017
Posts: 72
Re: A and B start running simultaneously. A r  [#permalink]

Show Tags

Yup. you are right.

Thanks, Re: A and B start running simultaneously. A r   [#permalink] 26 Feb 2019, 13:01
Display posts from previous: Sort by

A and B start running simultaneously. A r

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne  