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# a,b and c are consecutive integers where a<b<c. which

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VP
Joined: 22 Nov 2007
Posts: 1079

Kudos [?]: 678 [0], given: 0

a,b and c are consecutive integers where a<b<c. which [#permalink]

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16 Dec 2007, 05:00
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

a,b and c are consecutive integers where a<b<c. which of the following could not be the value of c^2-b^2-a^2?

A.-21
B.-12
C.-6
D.0
E.3

Kudos [?]: 678 [0], given: 0

CEO
Joined: 17 Nov 2007
Posts: 3584

Kudos [?]: 4580 [0], given: 360

Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40

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16 Dec 2007, 07:20
C

S=c²-b²-a²=(a+2)²-(a+1)²-a²=a²+4a+4-a²-2a-1-a²=-a²+2a+3

for a=0: S=3
a=-1: S=0
a=-2: S=-5
a=-3: S=-12
a=-4: S=-21

Kudos [?]: 4580 [0], given: 360

VP
Joined: 22 Nov 2007
Posts: 1079

Kudos [?]: 678 [0], given: 0

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16 Dec 2007, 09:14
nope...think also in a geometric way....

Kudos [?]: 678 [0], given: 0

16 Dec 2007, 09:14
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# a,b and c are consecutive integers where a<b<c. which

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