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# A, B and C play cricket. A's runs are to B's runs and B's

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Intern
Joined: 10 Nov 2004
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A, B and C play cricket. A's runs are to B's runs and B's [#permalink]

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01 Dec 2004, 15:06
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A, B and C play cricket. A's runs are to B's runs and B's runs are to C's as 3:2. They get altogether 342 runs. How many runs did A make?

(1) 162 (2) 108
(3) 72 (4) None of these

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Manager
Joined: 30 Jul 2004
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01 Dec 2004, 16:39
4 .......None of these

my answer is (340* 9) /19 ...it comes approx to 162...

My assumption is that A:B = 3:2 and B:C =3:2
pLS LET ME KNOW IF IT IS CORRECT.........

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Intern
Joined: 10 Nov 2004
Posts: 42

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01 Dec 2004, 16:49
I dont understand it but this is the answer

Solution:

A:B = 3:2 = 9:6;

B:C = 3:2 = 6:4 (making B equal)

Therefore, A:B:C = 9:6:4

Therefore, the runs made by A = (9/19) X 342 = 162.

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Senior Manager
Joined: 19 Feb 2004
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Location: Lungi

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01 Dec 2004, 18:32
A:B:C = 9:6:4
9x+6x+4x = 19x

Runs made by A = 9x/19x*342 = 162 ans A

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Senior Manager
Joined: 19 Feb 2004
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01 Dec 2004, 18:34
gmat+obsessed wrote:
4 .......None of these

my answer is (340* 9) /19 ...it comes approx to 162...

My assumption is that A:B = 3:2 and B:C =3:2
pLS LET ME KNOW IF IT IS CORRECT.........

gmat obsessed total runs are 342 and not 340. Ans is A

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Manager
Joined: 31 Aug 2004
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01 Dec 2004, 19:12

A:B=3:2
A/B=3/2
A=3B/2

B:C=3:2
B/C=3/2
C=2B/3

A:B:C can be rewritten as 3B/2:B:2B/3. If we divide every term by B and multiply every term by 6 to get rid of the denominator, we get 9:6:4.

So A:B:C=9:6:4, total is 9+6+4=19

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01 Dec 2004, 19:12
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