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A, B, C, and D are integers such that A - C + B is even and

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CEO
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Joined: 21 Jan 2007
Posts: 2734

Kudos [?]: 1076 [0], given: 4

Location: New York City
A, B, C, and D are integers such that A - C + B is even and [#permalink]

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New post 20 Nov 2007, 07:13
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A, B, C, and D are integers such that A - C + B is even and D + B - A is odd. Which of the following expressions is always odd?

a+d
b+d
c+d
a+b
a+c

Kudos [?]: 1076 [0], given: 4

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CEO
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Joined: 17 Nov 2007
Posts: 3583

Kudos [?]: 4662 [0], given: 360

Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
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 [#permalink]

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New post 20 Nov 2007, 07:57
C.

1. A-C+B=(A+B)-C even
2. D+B-A =(B-A)+D odd

C and D have opposite remainders.
Therefore,
C+D = odd

Kudos [?]: 4662 [0], given: 360

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B
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Kudos [?]: 443 [0], given: 49

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New post 20 Nov 2007, 08:14
A, B, C, and D are integers such that A - C + B is even and D + B - A is odd. Which of the following expressions is always odd?

a+d
b+d
c+d
a+b
a+c

add
A - C + B +D + B - A = 2b+d-c = odd , odd = even+odd
, 2b is even thus d-c is odd ie: any summision or subtroperation ,operations of c ,d is odd.

c+d is always odd

Kudos [?]: 443 [0], given: 49

  [#permalink] 20 Nov 2007, 08:14
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A, B, C, and D are integers such that A - C + B is even and

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