vishumangal wrote:
Bunuel VeritasKarishmaCould anyone explain me this question
On combining both statements if I take the value of X as 100 then in that case, C= A*D/B will not be Integer.....
the How can the C be divided by 5
For eg take A = 210, D=1 and B = 7^35, In this case C will not be divided by 5.
As per my knowledge if something is divisible by some integer the it should yield the remainder as 0
Using both statements together, A is divisible by 210 so A = 210m (where m is some positive integer)
B = 7^x where x is an integer.
So what will A/B look like?
\(\frac{A}{B} = \frac{210*m}{7*7*7* ...7*7}\)
\(\frac{A}{B} = \frac{7*2*3*5*m}{7*7*7* ...7*7}\)
\(\frac{A}{B} = \frac{2*3*5*m}{7*7*7* ... 7}\)
If m has factors of 7, some more 7s from the denominator could get cancelled but that is it. The lowest form of A/B will have at least 2, 3 and 5 in the numerator and MAY have some 7s in the denominator.
Since \(\frac{A}{B} = \frac{C}{D} = \frac{2*3*5*...}{7*7*... *7}\)
So C will have factors of 2, 3 and 5 too.
As for your example, if A = 210 and B = 7^35, D cannot be 1.
\(\frac{A}{B} = \frac{210}{7^{35}} = \frac{2*3*5}{7*7*... 7}\)
Now, if C = 2*3*5, D = 7*7*...*7
if C = 2*3*5*2, D = 2*7*7*...*7
and so on...
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