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a,b,c are three different numbers.None of the numbers equals the

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a,b,c are three different numbers.None of the numbers equals the  [#permalink]

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New post Updated on: 19 Apr 2017, 12:36
5
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

70% (02:16) correct 30% (02:45) wrong based on 54 sessions

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a,b,c are three different numbers.None of the numbers equals the average of the other two.
If \(\frac{x}{{a+b-2c}}\) = \(\frac{y}{{b+c-2a}}\) = \(\frac{z}{{c+a-2b}}\) , then what is the value of \(x+y+z\) ?

A)-1
B)5
C)3
D)1
E)0


Source-> NOVA.

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Originally posted by stonecold on 19 Apr 2017, 12:32.
Last edited by Bunuel on 19 Apr 2017, 12:36, edited 1 time in total.
Renamed the topic.
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Re: a,b,c are three different numbers.None of the numbers equals the  [#permalink]

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New post 19 Apr 2017, 12:36
3
1
Let

x/(a+b-2c) = y/(b+c-2a) = z/(c+a-2b) = k

which means

x = (a+b-2c)k
y = (b+c-2a)k
z = (c+a-2b)k

x+y+z = k*[a+b-2c+b+c-2a+c+a-2b] = k*0 = 0

Answer is E)0
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Re: a,b,c are three different numbers.None of the numbers equals the  [#permalink]

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New post 01 Sep 2018, 23:03
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: a,b,c are three different numbers.None of the numbers equals the &nbs [#permalink] 01 Sep 2018, 23:03
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a,b,c are three different numbers.None of the numbers equals the

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