GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 19 Oct 2019, 03:31

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# A, B, C, D, E, F, G, and H are all integers, listed in order of increa

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 58449
A, B, C, D, E, F, G, and H are all integers, listed in order of increa  [#permalink]

### Show Tags

04 Nov 2014, 09:37
3
52
00:00

Difficulty:

75% (hard)

Question Stats:

59% (02:26) correct 41% (02:36) wrong based on 548 sessions

### HideShow timer Statistics

Tough and Tricky questions: Sequences.

A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to 5^12 and 5^13, respectively, what is the value of A?

A. -24(5^12)
B. -23(5^12)
C. -24(5^6)
D. 23(5^12)
E. 24(5^12)

Kudos for a correct solution.

_________________
SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1749
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
A, B, C, D, E, F, G, and H are all integers, listed in order of increa  [#permalink]

### Show Tags

10 Nov 2014, 02:14
20
6
$$H = 5^{13}$$

$$G = 5^{12}$$

$$H - G = 5^{13} - 5^{12} = 4 * 5^{12}$$

A ......1....... B ........2....... C ........3......... D ..........4........... E ......5....... F ........6......... G ................... H

From point A, $$4 * 5^{12}$$ has to be added 6 times to reach point $$G = 5^{12}$$

$$A + 6* 4 * 5^{12} = 5^{12}$$

$$A = -23 * 5^{12}$$

_________________
Kindly press "+1 Kudos" to appreciate
##### General Discussion
Intern
Joined: 02 Jul 2014
Posts: 24
Location: United States
GPA: 3.24
WE: Engineering (Computer Software)
Re: A, B, C, D, E, F, G, and H are all integers, listed in order of increa  [#permalink]

### Show Tags

04 Nov 2014, 10:29
3
2
Bunuel wrote:

Tough and Tricky questions: Sequences.

A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to 5^12 and 5^13, respectively, what is the value of A?

A. -24(5^12)
B. -23(5^12)
C. -24(5^6)
D. 23(5^12)
E. 24(5^12)

Kudos for a correct solution.

Ans : B

Assume that the numbers appear as shown below on the number line

A-----B-----C-----D-----E-----F-----G-----H
| |
(5^12) (5^13)

As the values for G and H are given , we can calculate the difference between any two terms of the series .

Common Difference ,d = (5^13) - (5^12)
= (5^12) *[ 5-1 ]
= (5^12)*(4)

Also F + d = G as the terms are in equidistant and in increasing order.

So F + (5^12)*(4) = (5^12).

That is , F = (5^12) - (5^12)*(4)
= (5^12)[ 1-4]
= (5^12) (-3)

Similarly , E = F - d
= (5^12)[-3-4]
= (5^12)*(-7)

You can see a -4 getting added to the non-exponent part of the values . That is , according to the pattern , D SHOULD BE (5^12)*(-7-4)= (5^12)*(-11)
Following this pattern , A = (5^12)*(-23)

Ans : B
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 4009
A, B, C, D, E, F, G, and H are all integers, listed in order of increa  [#permalink]

### Show Tags

17 Nov 2015, 17:49
2
1
Bunuel wrote:

Tough and Tricky questions: Sequences.

A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to 5^12 and 5^13, respectively, what is the value of A?

A. -24(5^12)
B. -23(5^12)
C. -24(5^6)
D. 23(5^12)
E. 24(5^12)

H = 5^13
G = 5^12

Distance between H and G = 5^13 - 5^12
= 5^12(5^1 - 1)
= (5^12)(4)
= (4)(5^12)

So, F = 5^12 - (4)(5^12)
E = 5^12 - (4)(5^12) - (4)(5^12)
D = 5^12 - (4)(5^12) - (4)(5^12) - (4)(5^12)
C = 5^12 - (4)(5^12) - (4)(5^12) - (4)(5^12) - (4)(5^12)
B = 5^12 - (4)(5^12) - (4)(5^12) - (4)(5^12) - (4)(5^12) - (4)(5^12)
A = 5^12 - (4)(5^12) - (4)(5^12) - (4)(5^12) - (4)(5^12) - (4)(5^12) - (4)(5^12)

So, A = 5^12 - [(4)(5^12) + (4)(5^12) + (4)(5^12) + (4)(5^12) + (4)(5^12) + (4)(5^12)]
= 5^12 - (24)(5^12)
= (1)(5^12) - (24)(5^12)
= (-23)(5^12)

Cheers,
Brent
_________________
Test confidently with gmatprepnow.com
Target Test Prep Representative
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2815
Re: A, B, C, D, E, F, G, and H are all integers, listed in order of increa  [#permalink]

### Show Tags

16 Jan 2017, 18:12
1
Bunuel wrote:

Tough and Tricky questions: Sequences.

A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to 5^12 and 5^13, respectively, what is the value of A?

A. -24(5^12)
B. -23(5^12)
C. -24(5^6)
D. 23(5^12)
E. 24(5^12)

We are given that A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size, and that the distance between any two consecutive numbers, which we can denote by the variable n, is constant.

Since G and H are equal to 5^12 and 5^13, respectively, then the distance between them is:

n = 5^13 - 5^12

n = 5^12(5 - 1)

n = 5^12(4)

Since A is 6 numbers ahead of G, A is 6n less than G, and therefore:

A = G - 6n

A = 5^12 - 6[5^12(4)]

A = 5^12[1 - 6(4)]

A = 5^12[-23] = -23(5^12)

_________________

# Jeffrey Miller

Jeff@TargetTestPrep.com
122 Reviews

5-star rated online GMAT quant
self study course

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

Intern
Joined: 08 Jun 2017
Posts: 12
Re: A, B, C, D, E, F, G, and H are all integers, listed in order of increa  [#permalink]

### Show Tags

31 Aug 2017, 05:39
How I solved it is:
A, B, C, D, E, F, G, H (Total of 8 numbers = n)
Since its a sequence and each term is a certain constant more than the other.
H - G = 5^13 - 5^12 = (5^12) (5-1) = 4 x (5^12) = Our common difference, d.

Also unrelated,
G = A + (n-1) d
5^12 = A + (7-1) 4 (5^12)
As n=7, because its the 7th term in the sequence

Therefore,
A = (5^12) - 24 (5^12)
= (5^12) (1-24) Taking 5^12 common
= - 23 (5^12)
CEO
Status: GMATINSIGHT Tutor
Joined: 08 Jul 2010
Posts: 2978
Location: India
GMAT: INSIGHT
Schools: Darden '21
WE: Education (Education)
Re: A, B, C, D, E, F, G, and H are all integers, listed in order of increa  [#permalink]

### Show Tags

10 Sep 2018, 22:32
Bunuel wrote:

Tough and Tricky questions: Sequences.

A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to 5^12 and 5^13, respectively, what is the value of A?

A. -24(5^12)
B. -23(5^12)
C. -24(5^6)
D. 23(5^12)
E. 24(5^12)

Kudos for a correct solution.

Values of G and H are 5^12 and 5^13, respectively, and there is only one gap between them

so each gap between any two adjacent numbers = 5^13 - 5^12 = 5^12 (5-1) = 4* 5^12

order of numbers is A___B___C___D___E___F___G___H

A is 6 gaps smaller than G

i.e. A = 5^12 - 6*(4* 5^12) = -23* 5^12

_________________
Prosper!!!
GMATinsight
Bhoopendra Singh and Dr.Sushma Jha
e-mail: info@GMATinsight.com I Call us : +91-9999687183 / 9891333772
Online One-on-One Skype based classes and Classroom Coaching in South and West Delhi
http://www.GMATinsight.com/testimonials.html

ACCESS FREE GMAT TESTS HERE:22 ONLINE FREE (FULL LENGTH) GMAT CAT (PRACTICE TESTS) LINK COLLECTION
Manager
Joined: 06 Nov 2016
Posts: 58
Location: Viet Nam
GPA: 3.54
Re: A, B, C, D, E, F, G, and H are all integers, listed in order of increa  [#permalink]

### Show Tags

11 Sep 2018, 02:21
1
Let distance between any two consecutive numbers is d.
Distance between G and H is $$d= 5^{13} - 5^{12} = 4*5^{12}$$

Sequence {A, B, C, D, E, F, G, H}
A is the first term of sequence, G is the 7th term of sequence, thus: $$A +6d = G$$
-->$$A + 6*4*5^{12} = 5^{12}$$ --> $$A + 24*5^{12} = 5^{12}$$-->$$A = (-23)*5^{12}$$

Bunuel wrote:

Tough and Tricky questions: Sequences.

A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to 5^12 and 5^13, respectively, what is the value of A?

A. -24(5^12)
B. -23(5^12)
C. -24(5^6)
D. 23(5^12)
E. 24(5^12)

Kudos for a correct solution.

_________________
Manager
Joined: 14 Jun 2018
Posts: 217
Re: A, B, C, D, E, F, G, and H are all integers, listed in order of increa  [#permalink]

### Show Tags

11 Sep 2018, 12:11
Diff between last and second last term = 5^13 - 5^12 = 4 * 5^12
Since difference is constant , we can use decreasing AP. (changing this order from ascending to descending)
So 1st term is 5^13 and difference = - 4 * 5^12
= a + (n-1) d
= 5^13 + 7 * (- 4 * 5^12)
= 5^13 - 28* 5^12
= 5^12 * -23
Manager
Joined: 07 May 2018
Posts: 61
Re: A, B, C, D, E, F, G, and H are all integers, listed in order of increa  [#permalink]

### Show Tags

05 Jul 2019, 14:17
PareshGmat wrote:
$$H = 5^{13}$$

$$G = 5^{12}$$

$$H - G = 5^{13} - 5^{12} = 4 * 5^{12}$$

A ......1....... B ........2....... C ........3......... D ..........4........... E ......5....... F ........6......... G ................... H

From point A, $$4 * 5^{12}$$ has to be added 6 times to reach point $$G = 5^{12}$$

$$A + 6* 4 * 5^{12} = 5^{12}$$

$$A = -23 * 5^{12}$$

Quick question , could you please explain how you got 4*5^12?
Re: A, B, C, D, E, F, G, and H are all integers, listed in order of increa   [#permalink] 05 Jul 2019, 14:17
Display posts from previous: Sort by