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A bag has 100 marbles numbered consecutively 0 - 99 inclusive. Another

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A bag has 100 marbles numbered consecutively 0 - 99 inclusive. Another [#permalink]

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27 Sep 2010, 15:25
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55% (hard)

Question Stats:

47% (00:53) correct 53% (01:17) wrong based on 49 sessions

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A bag has 100 marbles numbered consecutively 0 - 99 inclusive. Another bag has 60 marbles numbered consecutively 90 - 149 inclusive. If a marble is randomly chosen from each bag, what is the probability that two marbles have the same number

1/10

1/60

1/100

1/600

1/6000
[Reveal] Spoiler: OA

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Re: A bag has 100 marbles numbered consecutively 0 - 99 inclusive. Another [#permalink]

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27 Sep 2010, 15:44
rxs0005 wrote:
A bag has 100 marbles numbered consecutively 0 - 99 inclusive. Another bag has 60 marbles numbered consecutively 90 - 149 inclusive. If a marble is randomly chosen from each bag, what is the probability that two marbles have the same number

1/10

1/60

1/100

1/600

1/6000

Common numbers : 90,91...99 total 10 numbers

probability = $$\frac{10}{{100*60}}$$ = $$\frac{1}{{600}}$$ = D
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Re: A bag has 100 marbles numbered consecutively 0 - 99 inclusive. Another [#permalink]

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27 Sep 2010, 15:47
No of ways to pick two marbles = 100*60 = 6000

No of ways to pick same number = (90,90) , ... , (99,99) = 10

So probability = 1/600
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Re: A bag has 100 marbles numbered consecutively 0 - 99 inclusive. Another [#permalink]

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27 Sep 2010, 20:50
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rxs0005 wrote:
A bag has 100 marbles numbered consecutively 0 - 99 inclusive. Another bag has 60 marbles numbered consecutively 90 - 149 inclusive. If a marble is randomly chosen from each bag, what is the probability that two marbles have the same number

1/10

1/60

1/100

1/600

1/6000

My approach:

Pickup the matching 10 numbered marbles from the first bag -- Probability - 10/100 -- 1/10

Now we have one of the marble numbered from 90 - 99. From the other bag we need to pick just the one marble which will have a number from 90 - 99 to ensure we have a matching marble set. Its probability is 1/60.

Hence combined probability is (1/10) * (1/60) -- 1/600. Answer D.

There is a similar question in this forum , check this out -- http://gmatclub.com/forum/junior-58914.html
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Re: A bag has 100 marbles numbered consecutively 0 - 99 inclusive. Another [#permalink]

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27 Sep 2010, 22:03
ezhilkumarank wrote:
rxs0005 wrote:
A bag has 100 marbles numbered consecutively 0 - 99 inclusive. Another bag has 60 marbles numbered consecutively 90 - 149 inclusive. If a marble is randomly chosen from each bag, what is the probability that two marbles have the same number

1/10

1/60

1/100

1/600

1/6000

My approach:

Pickup the matching 10 numbered marbles from the first bag -- Probability - 10/100 -- 1/10

Now we have one of the marble numbered from 90 - 99. From the other bag we need to pick just the one marble which will have a number from 90 - 99 to ensure we have a matching marble set. Its probability is 1/60.

Hence combined probability is (1/10) * (1/60) -- 1/600. Answer D.

There is a similar question in this forum , check this out -- http://gmatclub.com/forum/junior-58914.html

my approach.....

probability of picking a marble from 0 -99 in the first set = 1/100 { since 0-99 is hundred marbles}

similarly, probability of picking a marble from 90-149 in the second set = 1/60

therefore, probability that they are same = (1/100) * (1/60) = 1/6000

it can happen for 10 marbles ( 90 to 99 inclusive ) .

Thus, total probability = 10 *1/6000 = 1/600 ANS
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Re: A bag has 100 marbles numbered consecutively 0 - 99 inclusive. Another [#permalink]

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30 Sep 2017, 22:57
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Re: A bag has 100 marbles numbered consecutively 0 - 99 inclusive. Another   [#permalink] 30 Sep 2017, 22:57
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