goodyear2013 wrote:

A bird flies 60 meters at a constant speed from its nest to a nearby antenna, and continues 80 meters more, flying 5 meters per second faster, to perch on a window pane. The journey from the nest to the antenna takes the bird 4 seconds more than the journey from the antenna to the window pane. The bird flies how many seconds from its nest to the antenna?

A. 5

B. 8

C. 10

D. 12

E. 16

Let 'S' be the bird's speed from nest to a nearby antenna, then 'S+5' will be speed between Antenna and a window pane.

Given

\(\frac{60}{S} - \frac{80}{(S+5)} = 4\)

\(\frac{15}{S} - \frac{20}{(S+5)} = 1\)

now we can solve the quadratic equation , but we do not need to . In above equation S=5 . 3-2=1.

so answer is \(\frac{60}{5} = 12 Secs\)

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