Bunuel wrote:
A bouquet contains 16 flowers, each of them either a rose, tulip, daisy, or daffodil. If no two types of flower appear the same number of times in the bouquet, and there are more tulips than any other type of flower, what is the minimum number of tulips?
A. 4
B. 5
C. 6
D. 7
E. 8
A way to go about it is as follows,
As the number of tulips has to be minimum possible, with the given condition, we can agree that all the flower must be as close to each other as possible (can not be equal) and would have the average value of 4.
(how? 16/4=4)
Now let's divide the 4 numbers into two sets, if a>b>c>d, then a and d are one set and b and c are another
Hence the two numbers (in a set) will have to be at equal distances from 4 in opposite directions to have the same sum as 4+4, ie 4+1, coupled with 4-1 and 4+2 coupled with 4-2.
(Why not 4+0? because 4+0 = 4-0, hence the numbers become equal, which is not allowed)
Therefore clearly the closest (from each other) set of numbers fulfilling this questions conditions are 6,5,3,2
Therefore no. of tulips = 6.
Side note: This method only works because min value is asked, in the case of max, it is better to simply subtract the smallest possible values (1,2,3)
Please do leave a kudos if I could introduce a new method to you