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# a box contains 20 pieces of candies including maroon

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Director
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a box contains 20 pieces of candies including maroon [#permalink]

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21 Feb 2006, 17:15
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

a box contains 20 pieces of candies including maroon colored, silver colored, peach colored and red colored. If the number of peach colored is twice that of red colored, and maroon colored is 3 more than silver colored. What is the number of silver colored ones?

I) Number of Maroon colored is 1 more than that of red colored
II) Peach colred is 3 times that of Silver colred.
Manager
Joined: 13 Aug 2005
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21 Feb 2006, 19:10
It looks like D.
M+S+P+R=20
M=S+3 and P=2R
from that 2*S+3+3*R=20 stem
1) M=R+1 2*S+3+3*(M-1)=2*S+3+3*(S+3-1)=20 and can find S ( for silver) suf.

2) P=3*S => 2*R=3*S => can find S => suf
Manager
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21 Feb 2006, 20:05
it should be D ... same logic as natalya ....
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21 Feb 2006, 20:20
Total = 20
Maroon = m
Silver = s
Peach = p
red = r

p = 2r --(1)
m = s+3 --(2)

m+s+p+r = 20
s+3+2r+r = 20
s+3+3r = 20 ---(3)

s = ??

1) m = 1+r
r = m-1 = s+3-1 = s+2. We can substitute this to (3) to solve for s. Sufficient.

2) p = s+3
p/2 = r = (s+3)/2. We can substitute this to (3) and solve for s. Sufficient.

Ans D
Senior Manager
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21 Feb 2006, 21:59
Bingo... from stem 3x+4y = 20

1) -x+y = -6 , using 2 euqtions , we can solve - suffi

2) 2x-y=3 , using 2 equz , we can solve - suffi

D
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vazlkaiye porkalam vazltuthan parkanum.... porkalam maralam porkalthan maruma

Director
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23 Feb 2006, 03:51
you guys proved that the oa is D thanks!
23 Feb 2006, 03:51
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