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A can contains a mixture of 2 liquids A and B in proportion [#permalink]

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03 Jan 2005, 17:21

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A can contains a mixture of 2 liquids A and B in proportion 7:5.
9 liters of of the mixture is removed and 9 liters of B is added and the proportion of A and B becomes 7:9. How many liters of liquid A was originally in the can.

OA = 63

I could not figure this out i need a break i think

I am getting 21 lt as the ans. If x is the total liquid, then A is 7x/12 and 5x/12 for B. Take out 9 lt we have 7(x-9)/12 and B 5(x-9)/12 (assuming ratio doesn't change). Add 9 lt of B, then B becomes 5(x-9)/12 + 9.

So...(7(x-9)/12) / (5(x-9)/12 + 9) = 7/9 => x = 36. So A in original mix was 7(36)/12 ==> 21 lt.

I also got 21. I double checked to see if I got 7/9 using 21 as the answer and it checks out. Before I reduced the fraction when I was double checking I got 63/81, but that number is pretty meaningless. 21 has to be the right answer

A can contains a mixture of 2 liquids A and B in proportion 7:5. 9 liters of of the mixture is removed and 9 liters of B is added and the proportion of A and B becomes 7:9. How many liters of liquid A was originally in the can.

OA = 63

I could not figure this out i need a break i think

i could not get other than 21 lt. do you have explanations for 63 lt as answer?

A can contains a mixture of 2 liquids A and B in proportion 7:5. 9 liters of of the mixture is removed and 9 liters of B is added and the proportion of A and B becomes 7:9. How many liters of liquid A was originally in the can.

OA = 63

I could not figure this out i need a break i think

i could not get other than 21 lt. do you have explanations for 63 lt as answer? if yes, pls do post......................

guys thanks all for your answers the OA is 63 but no official explanation was given so it must be a typo in the book it happens but thanks all for trying

Did you simply solve the the equation "(7(x-9)/12) / (5(x-9)/12 + 9) = 7/9" for x.

I could not get 36. Maybe I am making an algebraic mistake but I cannot get 36, please explain the step above. (Thanks in Advance)

I understand that if the ratio is 7 parts to 5 parts equals 12 parts in total, then if the parts total increases to 36, the the ration is 7x3=21 / 5x3=15 or a new ration of 21/15 equals 36 parts in total (21 + 15).
Thanks much

I am getting 21 lt as the ans. If x is the total liquid, then A is 7x/12 and 5x/12 for B. Take out 9 lt we have 7(x-9)/12 and B 5(x-9)/12 (assuming ratio doesn't change). Add 9 lt of B, then B becomes 5(x-9)/12 + 9.

So...(7(x-9)/12) / (5(x-9)/12 + 9) = 7/9 => x = 36. So A in original mix was 7(36)/12 ==> 21 lt.

Not getting the OA u posted.

banarjee,

you have asut approaches to the problems. goodluck..........