this question is a application of AP. and yes the previous answers are correct.

Speed at time '0' = v0

Speed at time '10' = v10

Lets assume the speed is increasing at a rate of 'd' m/s

Note:- Distance traveled in any 1 second is equal to the speed during that second.Distance traveled in 1st sec = v0

Distance traveled in 2nd sec = v0+d

Distance traveled in 3rd sec = v0+2d

Distance traveled in 10th sec = v0+9d

So Total Distance traveled in 10 second can be given by

v0 + (v0+d) + (v0+2d)+.........+(v0+8d)+(v0+9d) = 10/2[2v0 + (10-1)d]=10/2[2v0 + 9d]

& as per question the bumper has traveled 125 m at the end of 10th second. So

10/2[2v0 + 9d]= 125

[2v0 + 9d]= 25

v0 + (v0+9d) = 25

v0 + v10 = 25......(1)

We are asked the value for speed at 0th & 10th second. From equation (1) we can say that the sum of speed at these moments is equal to 25.

The only options available are 5 , 20.

The speed v0 must be 5 & v10 must 20 because the speed is increasing at constant rate.

Note:- If the speed was decreasing at a constant rate, then v0=20 & v10=5Hope it helps.

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